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Re: Recommended Texbooks/Study Guides? Rofl. I wouldn't say that you're school has gotten it wrong, cause they actually know more than I do, I'm still a prelim student after all xD. But even if i am right, they are still providing you with a fairly decent textbook. On the other hand, the guys...

Re: Recommended Texbooks/Study Guides? Apparently for year 12, some concepts explained in jacaranda are misleading. As for Year 12 Spotlight, its information is much more accurate, or so I heard.

Png lol. im sure you cant tell from just that. He came to ask me, then he wouldn't believe me until i got 3 other people to tell him at school as well ==.

Awesome. Thanks guys :) I got a bit confused just then.

Re: 回复: Logarithms. ah so, if they give you logx they mean lnx unless stated otherwise?

Just a quick question. In an exam if you are given Log 2, is it assumed that the the log has a base of 'e' or '10' ? I always thought it was 'e' but my friend thinks otherwise. =/. Thanks for the help.

Holy crap. That's pretty hectic. :).

loooll. Apparently the laptops we're being provided with have a minimal amount of memory and can't be customised.

Whoa. You guys are awesome :). Thanks for the help.

Hey guys, sorry about this, but for some reason I can't remember how to integrate √(25-x²) Thanks in advance. <!--[if gte msEquation 12]><m:oMathPara><m:oMath><m:r>√</m:r></m:oMath></m:oMathPara><![endif]--><!--[if !msEquation]--><!--[if gte vml 1]><v:shapetype id="_x0000_t75"...

Whoa. That's rather hectic.

Coan said apparently you guys will probably do it during sport when we come back =/.

liar.

Re: Recommended Texbooks/Study Guides? Really =/?

ROFL. so true.

uh not sure about 1.. I'll try and help out later =/. Here's 2 x)

By doing that, you're getting the area under f(x) minus g(x) hence giving you a totally different area/answer

Um. I think you should go back to Aerath's post, he's explained it pretty well I'm not too sure what's happening there to be honest.

In the formula Δ h= mcΔ t c stands for the specific heat capacity of the solution in which the reaction is taking place. So in both reactions it would be 4.18 has they both occur in water.

Um. You could calculate how much energy has been absorbed by both, then comment on why both results differ. In turn, you could then suggest ways to improve your experiment =x. uh. Just for the record, i would have thought that the beaker would have absorbed less heat energy than the copper one...