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You don't need to be smart to do well in your HSC, just work your ass off

Nvm. Need to rethink this.

Is the answer B? EDIT: Checked it's B. So basically whenever the question mentions something about the acid being monoprotic etc, you assume that the acid fully ionises. So you know: n[NaOH] = c.v = (0.550) x (0.02950) ≈ 0.0162 mol So assuming full ionisation: n[citric acid] = (n[NaOH]) / 3...

How so? The spectator ions don't interact with the reactants or products in terms of electron transfer - that's why they're ignored in the net ionic equation.

It's to determine the movement of electrons - it'll come up a lot next year for you so get accustomed to it ;D

Haha that's the Westpac. ;P There's a different one where you have to provide answers with full working out from UNSW.

Or, you could man up and take 12. Jokes :P Do whatever you feel more comfortable with - if you want to concentrate on your 10 best units that you're absolutely sure you'll do well in.. go and do that.

Nah there are Junior and Senior divisions.

It's called the UNSW Mathematics Competition. Very original name haha The questions they ask you are outside the BoS syllabus for maths and they can potentially be very hard. You have to think laterally and carefully - marks are awarded for your method, not attaining the answer.

What's your aggregate like? Looks like 98-99 to me, just make sure those sciences cover your other two units well.

Just pick it up and drop it if it gets too much for you later in the year. It helps for MX1 as well because some of the methods you learn are very useful in the MX1 exam.

It's because buffer solutions contain a (weak) acid/base conjugate pair solution that effectively neutralises any acid or base left on the probe.

Lol JR should get out some more and play some other schools in sports.

Many thanks. :)

Can anyone evaluate: \int_{0}^{ \frac{ \pi }{2} } \frac{1}{1+(tanx)^{k}} \,dx Thanks. :)

4/11/10 = <3

Does touching mean the x and y axes are tangential to the circle?

Essentially an acid/base conjugate pair has a difference of one proton (an H) between them. The donor is the one with one more proton than the other, and so is the acid. The other is the base as it accepts it.

He meant your school's rank, not your aggregate rank

Haha yeah Asian 5. Thanks for the feedback guys :)