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nigga

LOL maybe which day you go?

yea me too, do u go burwood/hurstville

hey what tutor do you go to?

Proved that angle GDB= angle FCB, they proved cyclic quads twice and used perpendicular bisector theorem

I did this at tutor 2 weeks ago too lol

mx1:69/70 mx2:82/100

got like (a^2-b^2)/(a-b)^2 :s

woooo

probably bring up our school ranked to 50

YO i go to this mraznboys school. we only have 3U trials left

heres the solution for whoever: dv/dt=sqrt(h)/3 9r=0.4h (as they are both related) v=(pi)r^2h/3 v=pi(0.4h)^2.h/4 dv/dh=4pih^2/25 dh/dt=dh/dv . dv/dt dh/dt=25/4pi(h)^2 . sqrt(h)/10 =0.034cm/s

fml i know wat i did wrong, for some reason i changed sqrt(h)/3 to sqrt(h)/10 ye i got ur answer

hmm maybe i made a mistake in calculation imma recheck

Nah the past paper had no answers wasnt sure how to relate r and h so i just said that 9r=3.6h but its probably wrong

how do you get an equation with just r and h

essays were like all regurgitating stats

I wrote about globalisation, international organisations, australias government and other stuff which i forgot

browsin my cssa thread !