yay 20/20!
9 is definitely c. Single line stepping is when you go line by line through the code and check its logic. Program traces actually traces the variable's after each line.
I thought the railroad was pretty simple actually(i hope).
For a post test loop it will require Repeat ---> Until. In between it will be 1 or more of assignment statements, user input statements or conditional statements.
Nah, they mark whatever you write on the paper. Have a look at the band 6 responses in 2002, pretty much all of them write way more than the lines. http://arc.boardofstudies.nsw.edu.au/standards-packs/SP02_15030/
Im pretty sure since the test was straight forward they would mark it hard. For example the 5 marker on ADH and Aldosterone would probably be marked hard.
No, the band 6 cuttoff is determined by the bos markers depending on the ease of the test. It's usually not greater than 90. 90 is a band 6 moderated mark shown as the examination mark.
For 1996 6b)
Resolving forces tangentially and normally:
EFx = mrw^2 = F - mgCos0
Efy = 0 = mgSin0 + N
therefore F/N = (mrw^2 + mgCos0)/(-mgSin0)
= (rw^2 + gCos0)/(-gSin0)
check my solution, i did it really quickly
Our school uses Maths in focus as well, its pretty basic, but most of the time it gives you the correct theory. Do the excercises and get a book with all of the HSC questions and do them. I wouldn't recommend cambridge as they are not quite with the syllabus, especially for 4 unit maths.
I didn't actually write "a = 2a", i just put it in this thread to make it more obvious.
I got it wrong because the teacher wanted it done a different way, without t results for some reason. His method was about 10 steps longer than mine.
Prove that:
Cos2a = (1-tan^2a)/(1+tan^2a)
This was my proof, tell me if its ok please.
t = tan(a/2)
Cosa = (1-t^2)/(1+t^2)
but a = 2a
therefore cos2a = (1-tan^2a)/(1+tan^2a) as t = tan(2a/2) = tan(a)
Thanks
I'm doing this assignment and i need information on:
- Detailed use of indicators around the home
- The use of indicators in a variety of named industries.