Yeh i did bud.
Moles of Sodium Carbonate:
0.05 = Moles/0.02345
Therefore 2.345 x 10^-3 moles of HCL (Multiplying above answer by 2)
Molarity of HCL = (2.345 x 10^-3)/0.025
= 0.0938Mol/L
I got about 2643789kj and 55200L required for the hydrogen one. Im pretty sure its right, but i could be mistaken.
I got 0.098mol/L for the titration one as well.
I wrote that its a logic error and the program is stuck in an infinite loop because it is reading the same accountFile continuosly. It does not even stop when there are no more accountfiles to read.
But i didnt mention the "WHILE NOT found" should be "WHILE found = False".
In part iii) I did...
It's not usually that high. Mainly because most people choose the subject to bludge. 17/20 people in my class left after 1 hour of the test, so im guessing more people in the state will be like this too.
So band 6 cuttoff, bout 82-84/100.