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What kaz1 said, but mabey also hyperbole, because it is such a great exaggeration, that showcases the boundless love of the author...

We should be careful with the pepperared moth example, as I read an article last year in Nature, in which the said example, was experimented. I cannot fully remember the result of it, and neither the methodology nor conclusion, but it was against the original hypothesis proposed at the time. If...

o mybad typo. it was actually 16(m^2+m+1). Yea and i assume you complete the square etc... But say, the typically speaking, the discrim = 4(x^2+c^2+y^2) .... one would then say that; for all real values of x , c, y the discrim is >=0 thus more than 1 root exist etc... right?

Best of Luck for all people!!

nvm.

How did you get i)? I kept getting x = h/t

Yea ok, it perhaps will take a long time for me to be adept at these things. Thanks again kurt. Ive also a questionabout discriminants. Generally speaking, when proving that the discrimant is >0 , is it possible to just say using example find that discrim = 16(m^2+16m+1). And then state...

Can I just inquire kurt, when you approached this questions, what sort of method did you use. Did you approach this graphically etc... because in all trufully, this dosent make any sense to me whatsoever in why equn 1 was subbed into equn 2...

Yes it is correct. Thank you.

Na its better now. I recon that the admins are doing their best.

kurt?

If x and y are real and x+y=1, find the minimum value of 7x^2 - 4xy + 9y^2 and the values that x and y then assume

Sorry to bulge into thread, but how would one find the equation of a circle in the form of: (x+a)^2 + (y+b)^2 i.e. from the above. Really curious.

Heaps of Lag!

Thanks lychnobity! I see What about this question; show that the roots of the simultaneous equation x^2 + y^2 = 1 , 2ax + 2by + c =0 are real, provided that 4(a^2 + b^2 >= c^2. And also: If (a-b)^2 + (b-c)^2 + (c-a)^2 = 0 ; prove that a=b=c. Then, show that (x-b)(x-c)+(x-c)(x-a)+...

Find the value of K that will make equation perfect square. (3k-2)x^2 - 8x + (9k+7) Solving discriminate = 0 will give k=1 or -10/9 I just want to know, why -10/9 is discounted (as stated in the answer) and which step discount it?

Youve gota be 18+ to go right? Few more years yet.

After having watched some of those battle reports Ive got to admit, that even though I am WC3 at heart, SC2 does look very very interesting.

Another Question about limits: Q: find the value of x where 0<|x-2|<x so that when x is restricted to this domain, the different between x^2 and 4 will be numerically smaller than a) 0.1 ... c) e where e>0 From the examples of this Q, to solve and find the answer that x-2 < e/5 and thus x =...

But proof of his existence, and of his teachings would ADD WEIGHT to the proof of his divinty, would you not agree?