MedVision ad

2009 Question 7 & 8 (1 Viewer)

raniaaa

:)
Joined
Mar 21, 2008
Messages
480
Gender
Female
HSC
2009
yes, complex numbers, probability, locus, and extremely hard curve sketching
 

raniaaa

:)
Joined
Mar 21, 2008
Messages
480
Gender
Female
HSC
2009
these ones are. they have random i's and e's everywhere.. you're gonna cry when you see them :devil:
 

addikaye03

The A-Team
Joined
Nov 16, 2006
Messages
1,267
Location
Albury-Wodonga, NSW
Gender
Male
HSC
2008
In 1993 they asked a Q: prove that e^x=1+x+x^2/2!+x^3/3!+...

It's expected that they will ask for the power series expansion of sinx or cosx sometime:

sinx=x-x^3/3!+x^5/5!-...

and

cosx=1-x^2/2!+x^4/4!-...
 

addikaye03

The A-Team
Joined
Nov 16, 2006
Messages
1,267
Location
Albury-Wodonga, NSW
Gender
Male
HSC
2008
-Homogeneity in cosx and sinx

Example Q: sinx+cosx=1+sin2x

Solution: sinx+cosx=cos^2x+sin^2x+2sinxcosx

sinx+cosx=(cosx+sinx)^2

cosx+sinx=0 and cosx+sinx=1 etc

-Generating a telescoping sequence

Example Q: sinx+sin3x+...+sin(2n-1)x

Solution: times numerator and denominator by sinx

[(cos0-2x)+(cos2x-cos4x)+..+(cos(2n-1)x-cos2nx)]/2sinx

=sin^2nx/sinx

- First principles of integration (i.e. using upper bound and lower bounds rectangles which help generate inequalities or limits) or differentiaion (ie. log and exponential Q)

Example Q: Prove lim(n->inf) (1+x/n)^n=e^x

Solution: d/dx(Inx)=1/x.

d/dx(Inx)=lim(n->inf) [In(x+h)-In(x)]/h

1/x= lim(n->inf) In((x+h)/x)/h

1/x=lim(n->inf) In(1+h/x)^1/h

Ley y=1/x and let n=1/h

y=lim(n->inf) In(1+y/n)^n

rearranging

lim(n->inf) (1+x/n)^n=e^x

-Throw some geometry, probability, mechanics and recursion formulae

That's all i could think of/research
 

study-freak

Bored of
Joined
Feb 8, 2008
Messages
1,133
Gender
Male
HSC
2009
Note: I've heard that the exam commitee for this year's maths is a new one.
Thus questions can be more random than you think.
 

darusan92

Member
Joined
Aug 6, 2007
Messages
30
Gender
Male
HSC
2009
wen was the last time they changed it before this year?? if u can find that out u can look up the first paper they made and might be able to see how random their going to get!!!
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top