2012 Solutions -- Terry Lee (1 Viewer)

Artemkin

New Member
Joined
Apr 13, 2011
Messages
15
Gender
Male
HSC
2012
"x is the displacement"
"When is the displacement of the particle zero"
hence x=0
+1

I lost a mark on the bloody binomial question. Didn't account for n having to be an integer. :(
Reckon for 13c)ii) they'll accept an answer that's in km/hr rather than km/min?
 

manscux

Member
Joined
Oct 29, 2011
Messages
289
Gender
Male
HSC
2012
But i got terry lees answer i.e. 1.51 seconds but i used 5 .... could both methods work

actually kenkap.... i dont think that is right (i may be wrong).... x = 0 is a value on the number line

draw the number line and you will see that x=0 is in fact one of the extreme positions of the particle (max negative amplitude)

i think it is x=5
 

wilsondw

Member
Joined
Sep 3, 2011
Messages
241
Location
1.6180339887498948482045868343656
Gender
Male
HSC
2012
Do you guys reckon that they will give you 1 mark for the 2nd part of the probability question even though you got the first part wrong but u still managed to still use the correct binomial probablity form?
 

ahdil33

Member
Joined
Feb 28, 2011
Messages
183
Gender
Male
HSC
2012
The equation gave you the displacement of x. The particle was at the origin. therefore, x= 0.

Fairly pleased.
 

Kieran95

Member
Joined
Aug 8, 2012
Messages
199
Gender
Male
HSC
2012
Do you guys reckon that they will give you 1 mark for the 2nd part of the probability question even though you got the first part wrong but u still managed to still use the correct binomial probablity form?
You should get both marks i think, considering its correct from previous answer
 

traiwit

Member
Joined
Nov 11, 2011
Messages
243
Gender
Male
HSC
2012
Uni Grad
2016
Do you guys reckon that they will give you 1 mark for the 2nd part of the probability question even though you got the first part wrong but u still managed to still use the correct binomial probablity form?
I hope so man, i also got 1st part wrong
Hopefully we will get carry error
 

VJ30

Member
Joined
May 2, 2012
Messages
102
Gender
Male
HSC
2012
does anyone have an idea what 56/70 will align to???
 

NickGero

Member
Joined
Sep 8, 2012
Messages
33
Gender
Male
HSC
2012
For the displacement question, I subbed x = 0 into the displacement formula and the acceleration (x) formula and then formed two simultaneous equations with a and x and because of an algebra error it enabled me to solve the question and get an answer, despite having taken a very wrong method. Anyone wanna venture if I got any marks. I think its ridiculous they didn't say to 1d.p or 2 d.p, because it gives the impression of a neat answer.

If I get no marks for that, its 65/70, would be very happy if that can turn into 66 with a mark for this. Or possibly if I get 2/3 for the 3d trig question for having found multiple equations.
 

nucgaek

Member
Joined
Oct 5, 2011
Messages
68
Gender
Male
HSC
2012
For the displacement question, I subbed x = 0 into the displacement formula and the acceleration (x) formula and then formed two simultaneous equations with a and x and because of an algebra error it enabled me to solve the question and get an answer, despite having taken a very wrong method. Anyone wanna venture if I got any marks. I think its ridiculous they didn't say to 1d.p or 2 d.p, because it gives the impression of a neat answer.

If I get no marks for that, its 65/70, would be very happy if that can turn into 66 with a mark for this. Or possibly if I get 2/3 for the 3d trig question for having found multiple equations.
Pretty sure you'll get 0... they can read for a BS answer and they'll give you 0 unless you were on the right track
 

7eleven

Member
Joined
Sep 16, 2012
Messages
237
Gender
Male
HSC
N/A
Do you guys reckon that they will give you 1 mark for the 2nd part of the probability question even though you got the first part wrong but u still managed to still use the correct binomial probablity form?
Yeah u will
It called a "carry over". They cant penalise u twice for the same mistake.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top