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2012 Year 9 &10 Mathematics Marathon (1 Viewer)

Fawun

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Re: 2012 Year 9 &10 Mathematics Marathon

I dont understand this - many times you have to get it wrong to learn. You cant win if you dont play the game. This thread is the place to make mistakes.
Yeah but everyone else such as kaze and kev already know it and like are already looking into other ways to solve it whilst I haven't even gotten the easy way... makes me look dumb.
 

Fawun

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Re: 2012 Year 9 &10 Mathematics Marathon

Okay let me try
 

Fawun

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Re: 2012 Year 9 &10 Mathematics Marathon

So the imaginary perpendicular line that bisects BC from A I shall call AD. Now, RHS is Right Angle, Hypotenuse and Side.

In Triangle ADC,

Angle ADC is a right angle at 90 degrees (since AD bisects BC)
AC is the hypotenuse
DC is the side

????

WTF
 

kev-

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LOL, I don't know if this is valid or not, and it's not elegant but i'll still post it up.
rhombus.JPG

so a=c and b=d, diagonals bisect the angles
a=d and b=c, parallel lines.
so a=b and d=c.
 

deswa1

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@Fawun- do you know circle geometry? If so, there's a nice question that Carrot showed me that you could try (though it could be too difficult...)
 

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