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2017 HSC Mathematics Paper thoughts (1 Viewer)

Sxerks3

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It wasn't too bad, I'm looking at around 93/94 to 96 raw, depending on how harshly they mark it.
Screwed up the loan repayment, as I put it = 0, instead of 80,000.
Couldn't factorise dL/dx to find x.
Everything else was alright.
 

1729

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This is still subject to review, but apparently a GP with r=0 cannot exist to form a limiting sum of 2, as a=2 for that to occur. Thus your series is 2+0+0+0+0,..... Term2/Term1=0/2=0 but Term3/Term2=0/0=undefined. So a GP must have a non-zero common ration, if 'a' is a non-zero number. Which means the answer may be 0<a<4, a is not equal to 2 (when r=0). Pretty sure this question was designed to trick the state though, so I'm not sure how they'll receive it in the marking center. But it is 3 marks, so other than rearrange the question or graphing/determining the range for 2 marks, the other one is likely gained by recognizing the restriction.

The only case where a zero GP may exist is when 'a'=0 i.e. 0,0,0,0,... which doesn't provide a limiting sum of 2.
?
 

PARLIAMO314159

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I'm also wondering this.
Yep, as the mathematics you used to attain either answer is correct, as you rounded to 2 sig figs, and they didn't specify to use the rounded value of k in part iii, i.e., through using the directive 'hence', etc. Essentially, if the method's correct, they'll accept the solution, especially considering that sizeable proportion of the 2017 2u/3u cohort would've answered part iii using the rounded figure.
 

1729

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This is still subject to review, but apparently a GP with r=0 cannot exist to form a limiting sum of 2, as a=2 for that to occur. Thus your series is 2+0+0+0+0,..... Term2/Term1=0/2=0 but Term3/Term2=0/0=undefined. So a GP must have a non-zero common ration, if 'a' is a non-zero number. Which means the answer may be 0<a<4, a is not equal to 2 (when r=0). Pretty sure this question was designed to trick the state though, so I'm not sure how they'll receive it in the marking center. But it is 3 marks, so other than rearrange the question or graphing/determining the range for 2 marks, the other one is likely gained by recognizing the restriction.

The only case where a zero GP may exist is when 'a'=0 i.e. 0,0,0,0,... which doesn't provide a limiting sum of 2.
The syllabus only places restriction |r| < 1 for limiting sum
 

shehan123

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The syllabus only places restriction |r| < 1 for limiting sum
This is true, we never go over the case of R=0, but then the man spits a good point, 3 marks for that 0 < a < 4 seems a little dodgy.
 

Jaaames007

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Would anyone that is experienced with the hsc know the cut off mark for a bank 6 for this years paper. Thankyou
 

silverdawn565

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Last edited:

camstu

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Easier than what I expected.
How did people do the proof question at the end of 16? It was probably obvious but I ended up skipping the 3 mark cuz I couldn't wrap my head around it at the time (Part i. Prove that triangle ACE is isosceles) and doing the 2 mark (part ii).

Maths Solutions
http://community.boredofstudies.org/1234/mathematics/370356/2017-hsc-maths-exam-solutions.html
I did the exact same, I spent a bit of time proving similar triangles and what not but didn't get anywhere, by the looks of what everyone else is saying I doubt I will get marks for that but I hope they are generous to give me at least one mark.
 

silverdawn565

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I did the exact same, I spent a bit of time proving similar triangles and what not but didn't get anywhere, by the looks of what everyone else is saying I doubt I will get marks for that but I hope they are generous to give me at least one mark.
Looking at the solutions I think I should have revised proofs to do with parallel lines. Ratio of intercepts of parallel lines just didn't occur to me. And it's funny cuz during the exam I thought BD=DE but just didn't know how to prove it. But yea, hopefully you can score a mark for writing something down for proving similar triangles.
 

camstu

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Looking at the solutions I think I should have revised proofs to do with parallel lines. Ratio of intercepts of parallel lines just didn't occur to me. And it's funny cuz during the exam I thought BD=DE but just didn't know how to prove it. But yea, hopefully you can score a mark for writing something down for proving similar triangles.
got out of the exam room and thought 'i wonder if they told us BM=MC for a reason?' turns out they did and I just didn't do anything with it
 

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