Ah, of course.SoulSearcher said:It's solving the equation sin23@ - sin2@ = sin2@ for the range 0 < x < pi, not proving it
Ah, of course.SoulSearcher said:It's solving the equation sin23@ - sin2@ = sin2@ for the range 0 < x < pi, not proving it
Dividing by zero from line 3 to 4: a=b <=> a-b=0drynxz said:well whats wrong with this proof ?
first..let a=b
1) ab=a^2
2) ab-b^2=a^2-b^2
3) b(a-b)=(a+b)(a-b)
4) b=a+b
5) b=2b
6) 1=2.
which line has a error and why...?
That's some nice illegal maths there, unfortunately Riviet's question still needs answeringdrynxz said:well whats wrong with this proof ?
first..let a=b
1) ab=a^2
2) ab-b^2=a^2-b^2
3) b(a-b)=(a+b)(a-b)
4) b=a+b
5) b=2b
6) 1=2.
which line has a error and why...?
I tried that for a day once. Felt like too much overloaded in a page so I switched back to default. Okay, no more spam please (unless you're posting to answer a question), otherwise I'll have to bump my question to the next page.SoulSearcher said:50 posts per page ftw
Riviet said:For everyone's convenience of not having to go back to the previous page:
Next Question:
In a complex pulley system, the length of rope L needed for operation and the distance x m from a specific pulley to the centre of the system is defined by:
L=(x2-20x+136)1/2 + (x2+64)1/2
Find the distance x m that the pulley should be from the centre of the system that minimises the length of rope required.
i dont really know how i would write the answer/cant be bothered coz of all the working but my answers are:Affinity said:Stephen has a loan of 100,000.00 to pay. each month, interest of 0.8% is charged on the outstanding amount
a) If stephen pays 5,000 each month starting one month from now how long will it take him to repay the loan?
b) Now suppose stephen pays different amounts every months, but according to the rule that for every dollar of the balance, he'll pay eight cents, so he'll pay more initially, but less later. Find the outstanding amount after the n-th payment