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2Unit Mathematics 2007 Solutions (1 Viewer)

747nick

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Mar 10, 2007
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Hey!

Great job, thanks for the solutions!

One question though. For question 5 b) ii) (which leads me in to getting iii wrong).

Differentiating velocity we get:

2(16+t^2) - 4t^2 (please disregard the bottom for now)
= 32 + 2t^2 - 4t^2
= 32 - 2t^2 => -2(16+t^2)
on the bottom we have (16+t^2)^2 - can we not cancel these two out?

Hence, giving us -2t/16+t^2

I'm probably wrong, I just hope I get the marks for getting to the correct point...maybe the markers will disregard my simplification?

Leading in to iii), letting a = 0, the whole bottom goes bye bye as you can see with my simplification. So I said the particle is always accelerating :( (one weird particle)
 

747nick

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Mar 10, 2007
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2007
Nevermind :( I'm an idiot!!!

Expand -2(16+t^2) = -32 - 2t^2 .... thats not the same as 32 - 2t^2 is it.

My bad.
 

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