Application of calculus (1 Viewer)

Saturn WY15

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Q24 ) Circular cylinder of height 6cm and base radius of 4cm sits on a table with its axis vertical. A point source of light moves vertically upward at a speed of 3cm/s above the central axis of the cylinder, thus creating a circular shadow on the table. Find the rate at which the radius of the shadow is decreasing when light is at a distance 4cm above the top of cylinder .
 

bleakarcher

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one second mate, working on it for ya. why are the forums so inactive here lately?
 

bleakarcher

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Let the height of the light source above the top of the cylinder after some time t from when the light source began moving be h. Let the radius of the shadow after this time t be r. By similar triangles it follows that:
=> r/4=(h+6)/h
i.e. r=4+(24/h)
Differentiating implicitly with respect to time t:
=> dr/dt=(-24/h^2)*(dh/dt)
Since dh/dt=3,
=> dr/dt=-72/h^2
When h=4,
=> dr/dt=-72/4^2=-4.5 cm/s
Hence, the radius of the shadow is decreasing at a rate of 4.5 cm/s when h=4.

Hope this helped :)
 

Saturn WY15

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Let the height of the light source above the top of the cylinder after some time t from when the light source began moving be h. Let the radius of the shadow after this time t be r. By similar triangles it follows that:
=> r/4=(h+6)/h
i.e. r=4+(24/h)
Differentiating implicitly with respect to time t:
=> dr/dt=(-24/h^2)*(dh/dt)
Since dh/dt=3,
=> dr/dt=-72/h^2
When h=4,
=> dr/dt=-72/4^2=-4.5 cm/s
Hence, the radius of the shadow is decreasing at a rate of 4.5 cm/s when h=4.

Hope this helped :)
Thanks man you are absolute life-saver !!! Keep up the good work :)
 

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