BoS Trials Maths 2025 (1 Viewer)

barnyard

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It's acting with the motion. If it was acting against the motion, the wording would ordinarily call it a resistance force and the object would be decelerating. It was also kind of implied in the question that the force caused the object to accelerate in the positive direction and we now want to make it accelerate even more.

Question has now been reworded to make that clearer.
well thats good news, that what i put!
also, maybe a bit of a hard to answer question, but ive been looking through past bos trial results and im just wondering how these raw marks would "scale" in comparison to raw marks in the hsc going to scaled and aligned ykwim? like, do people who've achieved x in the bos trials usually go on to get a hsc mark that's in some way related to x?
 

Trebla

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well thats good news, that what i put!
also, maybe a bit of a hard to answer question, but ive been looking through past bos trial results and im just wondering how these raw marks would "scale" in comparison to raw marks in the hsc going to scaled and aligned ykwim? like, do people who've achieved x in the bos trials usually go on to get a hsc mark that's in some way related to x?
I don't exactly ask BoS trial students for their actual HSC marks so I cannot tell you...

All I can say is you don't necessarily have to ace the BoS Trials to state rank in the HSC. Students who have topped the BoS Trials did not necessarily state rank. But obviously this is at the top end of the scale where just 1-2 marks makes a difference.
 

tyson_mikey

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It's acting with the motion. If it was acting against the motion, the wording would ordinarily call it a resistance force and the object would be decelerating. It was also kind of implied in the question that the force caused the object to accelerate in the positive direction and we now want to make it accelerate even more.

Question has now been reworded to make that clearer.
Ah that got me, I was really confused as for it to be the acute angle and driving force it needed to be the angle from the left side of the diagonal, perhaps the better way to think of it would be as a rope and tension?
 

Trebla

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Ah that got me, I was really confused as for it to be the acute angle and driving force it needed to be the angle from the left side of the diagonal, perhaps the better way to think of it would be as a rope and tension?
Could it be because you're thinking of having the force vector's tip on the object from the left? Any force vector acting on the object should be illustrated with its tail on the object's centre.
 

tyson_mikey

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Could it be because you're thinking of having the force vector's tip on the object from the left? Any force vector acting on the object should be illustrated with its tail on the object's centre.
I was thinking kind of like this diagram so I thought it has to be resistive as the driving force would have to have an obtuse angle to the horizontal, idk what I was thinking for q2, def overcomplicated it 1759841417843.png
 

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