Chem calculations! (1 Viewer)

[hobozforlife]

Ozone reacts with nitric oxide according to the equation:
NO(g) + O3 (g) → NO2(g) + O2(g)
0.33 g NO(g) was mixed with 0.36 g O3(g).
What is the maximum volume of O2 (g) produced at 0°C and 100 kPa?

 

[Obvious]

Off the top of my head:

n(NO) = 0.33 g / 30 gmol^-1 = 0.011 mol

n(O₃) = 0.36 g / 48 gmol^-1 = 0.0075 mol

Since the stoichiometry is 1 : 1, ozone is the limiting reagent.

n(O₂) = 0.0075 mol

V = 0.0075 mol x 22.71 Lmol^-1 = 0.17 L

Double check the 22.71, I'm not sure if that's the true value

 

[hobozforlife]

Yo that's right, thanx
btw so when u get two different values for moles you use the highest one?