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Chemistry Predictions/Thoughts (9 Viewers)

HappyTheSkibidi

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Gyatt that’s a b6 at least
Tbh I probably did similar but I’m too scared to calculate
Genuinely I think it could be lower then that. I know I'm defo gonna drop marks because of phrasing. What shocks me is question 29. apprently 0 change happens
 

C2H6O

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for qn 34 a)does this come into play?
View attachment 50280
I did half eq pt at first but then realised the log scale is gonna fk it up there’s no way you’re gonna get exact answer by eyeballing it
So I calculated but used eq pt and got like 7E-5 but apparently I was supposed to use the initial pH and actual answer was like 4E-5 or something.
I did sanity check by finding pH at half eq pt though and got pH at half eq pt 4.15 which looks very close so idk, maybe made errors but I swear I triple checked that sht so prolly just wrong approach.
 

HappyTheSkibidi

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I did half eq pt at first but then realised the log scale is gonna fk it up there’s no way you’re gonna get exact answer by eyeballing it
So I calculated but used eq pt and got like 7E-5 but apparently I was supposed to use the initial pH and actual answer was like 4E-5 or something.
I did sanity check by finding pH at half eq pt though and got pH at half eq pt 4.15 which looks very close so idk, maybe made errors but I swear I triple checked that sht so prolly just wrong approach.
It is possible though, js search up Cognito 2025 Chem solutions and it's there
 

C2H6O

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It is possible though, js search up Cognito 2025 Chem solutions and it's there
Yes I agree it’s possible, I initially did eyeball pH 4.2 at half eq at first then sanity check with eq pt calc and it got far off enough to be concerned (well maybe it wasn’t far off bc value is very small but the first digit didn’t line up). And considering that other method gives pH 4.15 at half eq makes it difficult to distinguish. Dk how they’re gonna mark cause lots of ppl did use half eq pt so error margin might be wider or they might have expected some knowledge that it’s inaccurate to eyeball, not sure but apparently I got it wrong anyway.

Is the answer confirmed ~4E-5?
 

eternallyboreduser

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Nah don't think so, as long as you drew it out or gave some indication of what it was,
Is it just me or was this paper genuinely one of the easiest one yet?
Hell nah the previous ones easier imo - but its so subjective cos it depends on what ur good at. If ur better at calcs i reckon youd be better with exams like 21-24, but if ur better w explanations then this test is probably easier. Lowkey tripped me up though cos i wasnt expecting an exam with so many explanations
 

C2H6O

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Hell nah the previous ones easier imo - but its so subjective cos it depends on what ur good at. If ur better at calcs i reckon youd be better with exams like 21-24, but if ur better w explanations then this test is probably easier. Lowkey tripped me up though cos i wasnt expecting an exam with so many explanations
Same bro everyone saying 2021 was hard.. it was most straightforward imo
It’s not that this paper was hard it’s just very unlike previous papers, much more explanation/drawing, and calcs were not your usual questions. Also it’s just the trick questions and a ton of them. I guess it jsut caught me off guard so I’m over stressing (hopefully)
 

Olau

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For q29 (argon gas added one), does anyone think adding argon gas increases pressure = equilibrium shift? Cuz cognito answers doesn't think so.
 

TheOneTrueStudent

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For q29 (argon gas added one), does anyone think adding argon gas increases pressure = equilibrium shift? Cuz cognito answers doesn't think so.
idk I was gonna say it didn't affect the equilibrium but then i saw it was a 4 marks and I was tripped out
 

BionicMango

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For q29 (argon gas added one), does anyone think adding argon gas increases pressure = equilibrium shift? Cuz cognito answers doesn't think so.
No bc there’s the same number of moles for the two species, and the same volume, so the concentrations of both will be the same, so no change.
Temperature doesn’t change because the ideal gas law tells us that PV = nRT and since n increases P increases without needing T to increase. So if nothing related to Keq changes then there is no change in the system.
 

lucas10champ

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No bc there’s the same number of moles for the two species, and the same volume, so the concentrations of both will be the same, so no change.
Temperature doesn’t change because the ideal gas law tells us that PV = nRT and since n increases P increases without needing T to increase. So if nothing related to Keq changes then there is no change in the system.
how is this 4 marks tho
 

mangoes_4

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I think for the argon gas question they will award marks to both cases.
Its cruel to be misleading us with the temperature and making it 4 marks.
At least make the question: Will equillibrium shift when argon gas is added? 2 marks -this will make students actually think
im so confused with that? I was immediately like yeah it doesnt affect it, but what do i write for 4 marks
 

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