Complex Number Q; finding complex solutions and locus Q (1 Viewer)

[lil-angeliz]

hey guys got these two questions which are driving me nuts, as i found so many answers and i know they are all wrong.
_
3|z|^2 + z ^2 + 2z = 0
_
how would u draw the locus |z|=2 (i know its a circle with radius 2) and the locus z= z .

PLEASE HELP!!!

 

[lil-angeliz]

it didnt work out when i posted, sorry guys but the conjugate line is menat to on top of z^2 (the second term). Also this is menat to be the case for the locus graph where z=conjugate z.

 

[Timothy.Siu]

hey guys got these two questions which are driving me nuts, as i found so many answers and i know they are all wrong.
_
3|z|^2 + z ^2 + 2z = 0
_
how would u draw the locus |z|=2 (i know its a circle with radius 2) and the locus z= z .

PLEASE HELP!!!

locus of |z|=2 is just circle with radius 2 at the origin like you said, this is because |z|=root(x^2+y^2)=2 therefore x^2+y^2=4
locus of z=z' is just the line y=0 since if a conjugate equals the other one, the number is real

 

[vds700]

do u mean
?

 

[shaon0]

do u mean
?

If she means; 3(mod(z)+z^2+2z=0
=> 3z(z bar)+z^2+2z=0
z(3(z bar)+z+2)=0
Let z=x+iy and you'll get z=-0.5 or 0