Dot point help (1 Viewer)

mrpotatoed

Active Member
Can anyone show me how to do:

1.71 (no idea how to do this)

1.73(b): I subbed in n=3, n=6 to the equations for final and initial respectively (and then reciprocated) but got the wrong answer.

Both questions from quanta to quarks area

Fizzy_Cyst

Well-Known Member
Post the questions?

mrpotatoed

Active Member
"use the rhyberg equation to calculate the ionisation energy of hydrogen" \

Im guessing the final shell would be infinity, initial is one, and use just sub that in, but I get 10.something when it should be 13.6

The other question is a diagram that asks to calculate the wavelength of the photon of highest energy in the Paschen series which can be found here https://upload.wikimedia.org/wikipedia/commons/thumb/b/b2/Hydrogen_transitions.svg/400px-Hydrogen_transitions.svg.png

highest energy photon would be when an electron drops from shell 6 to 3, right? So I tried subbing those values (and tried other possible electron paths also) into the rhyberg equation but got it wrong so not sure what to do

anomalousdecay

The other question is a diagram that asks to calculate the wavelength of the photon of highest energy in the Paschen series which can be found here https://upload.wikimedia.org/wikipedia/commons/thumb/b/b2/Hydrogen_transitions.svg/400px-Hydrogen_transitions.svg.png

highest energy photon would be when an electron drops from shell 6 to 3, right? So I tried subbing those values (and tried other possible electron paths also) into the rhyberg equation but got it wrong so not sure what to do
Put shell infinity to 3. Does this give you the answer? It would make sense because it is asking you for the highest energy emission, would be that of smallest wavelength.

Putting,

$\bg_white \frac{1}{n^2} = 0 \ , \ \ So n \rightarrow \infty \ ,$

will yield the highest energy output.

https://en.wikipedia.org/wiki/Hydrogen_spectral_series as a reference if need be.

Fizzy_Cyst

Well-Known Member
"use the rhyberg equation to calculate the ionisation energy of hydrogen" \

Im guessing the final shell would be infinity, initial is one, and use just sub that in, but I get 10.something when it should be 13.6
13.6eV is the correct value for the ionisation energy of Hydrogen, so must be plugging something incorrectly into your calculator?

Drsoccerball

Well-Known Member
Which module is this ?...

th4st00g3

New Member
Why did you use shell 3? Is that the shell that a hydrogen electron sits in?

pikachu975

I love trials
Moderator
Why did you use shell 3? Is that the shell that a hydrogen electron sits in?
The Paschen series is when an electron drops from n = ? to n = 3, thereby releasing infrared radiation.