That's what I got, but make sure that you use 18.3%, 36%sarevok said:Confidence interval:
18.3% < u < 36%
Murray said the textbook was wrong to use equal or less than signs.
However, murray = dick.
That's what I got, but make sure that you use 18.3%, 36%sarevok said:Confidence interval:
18.3% < u < 36%
sarevok said:3g)
ii) o^2(x+y) = o^2(x) + o^2(y) + 2cov(x, y)
Var(3x - 2y + 1) =
Var(3x) + Var (-2y) + 0 =
3^2(Var x) + -2^2Var(y) + 2cov(x, y)
Var(x) = 16^2 = 256
Var(y) = 4^2 = 16
Therefore,
3^2(256) + (-2)^2(16) - 20 = 2220
I just confirmed that this is right from the lecture notes (wk 6).04er said:when we have something like X~N(50,25) does that mean X~N(Mean,Variance) i.e. X~N(Mean,Std_Dev^2)?
what questions did you get?jpr333 said:Yes yes you should, had the quiz today easy questions, think I'll get 10.
.................what questions did you get?
i envy you...jpr333 said:I had the equivalent of qs 1(c), 2(b) and 3(a)
I got the same questions for 1 and 2, and for 3 I got 3(d) with just some numbers changed. So glad... I just couldn't get those proportion formulas to stay in my head.1Time4thePpl said:i got a Z>whatever Q1.
X~N(10,64) P(X<64) Q2
and cant remember what for Q3. Really simple one though. Just a normal find the z value of a sampling distribution Q.
Go back to what the definition of covariance is (ref: pg 169-170 textbook). If X and Y are independent, covariance would be equal to zero because there is no relationship between discrete random variables X and Y (whatever happens to X, there is no effect on Y).04er said:someone please help me with 3. g) iii) !!!!!!!! or at least refer me to a page... please
Thank you for your help Lainee and jpr333 and SarevokLainee said:Go back to what the definition of covariance is (ref: pg 169-170 textbook). If X and Y are independent, covariance would be equal to zero because there is no relationship between discrete random variables X and Y (whatever happens to X, there is no effect on Y).
Lainee to the rescue... you're my hero! hehehe Do you know where to find the proof for 3k?Lainee said:2(d) is pretty straightforward use of the formula on page 237 of the textbook 'Finding Z for the sampling distribution of the mean'.