Extension Maths Query (1 Viewer)

Finx

Member
Joined
Mar 29, 2008
Messages
375
Gender
Male
HSC
2009
2. i) Show that 1/(p^2+pq) + 1/(q^2+pq) = 1/pq

I figured this one out, but for the next bit:

ii) Hence express 1/5 in the form 1/a + 1/b for some positive integers a and b.

What the hell does this mean? >_<
 

bored of sc

Active Member
Joined
Nov 10, 2007
Messages
2,314
Gender
Male
HSC
2009
Maybe:
Let p = 1 and q = 5.

Substitute it the equation of part (i)
= 1/(12 + 1x5) + 1/(52 + 1x5)
= 1/6 + 1/30

Therefore a = 6 and b = 30.

Hmm...
 
Last edited:

shaon0

...
Joined
Mar 26, 2008
Messages
2,029
Location
Guess
Gender
Male
HSC
2009
Finx said:
2. i) Show that 1/(p^2+pq) + 1/(q^2+pq) = 1/pq

I figured this one out, but for the next bit:

ii) Hence express 1/5 in the form 1/a + 1/b for some positive integers a and b.

What the hell does this mean? >_<
LHS=1/(p^2+pq) + 1/(q^2+pq)
=q^2+2pq+p^2/(q^2+pq)(p^2+pq)
=(p+q)^2/q(p+q)*p(p+q)
=(p+q)^2/pq(p+q)
=(p+q)/pq...
What is your solution for the first part?

ii) Let a=p(p+q), b=q(p+q), pq=5
Sub a value into b value.
b-q^2=a-p^2
(p-q)(p+q)=a-b
p+q=(a-b)/(p-q)
 
Last edited:

lyounamu

Reborn
Joined
Oct 28, 2007
Messages
9,997
Gender
Male
HSC
N/A
Finx said:
2. i) Show that 1/(p^2+pq) + 1/(q^2+pq) = 1/pq

I figured this one out, but for the next bit:

ii) Hence express 1/5 in the form 1/a + 1/b for some positive integers a and b.

What the hell does this mean? >_<
1/(p^2+pq) + 1/(q^2+pq) = 1/pq

1/5 = 1/(5 x 1)
= 1/(5^2 + 5 x 1) + 1/(1^2 + 5 x 1) = 1/30 + 1/6

Therefore, a = 30 and b=6 as bored of sc said.
 

Finx

Member
Joined
Mar 29, 2008
Messages
375
Gender
Male
HSC
2009
shaon0 said:
LHS=1/(p^2+pq) + 1/(q^2+pq)
=q^2+2pq+p^2/(q^2+pq)(p^2+pq)
=(p+q)^2/q(p+q)*p(p+q)
=(p+q)^2/pq(p+q)
=(p+q)/pq...
What is your solution for the first part?
LHS:
= 1/p(p+q) + 1/q(p+q)
After multiplying by q/q and p/p respectively
= q/pq(p+q) + p/pq(p+q)
= (p+q)/pq(p+q)
= 1/(p+q)

1/(p^2+pq) + 1/(q^2+pq) = 1/pq

1/5 = 1/(5 x 1)
= 1/(5^2 + 5 x 1) + 1/(1^2 + 5 x 1) = 1/30 + 1/6

Therefore, a = 30 and b=6 as bored of sc said.
Ah I see, p=5 and q=1 (for the positive factors of 5), then after subbing etc you get the 1/30 and 1/6. Sweet, thanks =D
 

shaon0

...
Joined
Mar 26, 2008
Messages
2,029
Location
Guess
Gender
Male
HSC
2009
Finx said:
LHS:
= 1/p(p+q) + 1/q(p+q)
After multiplying by q/q and p/p respectively
= q/pq(p+q) + p/pq(p+q)
= (p+q)/pq(p+q)
= 1/(p+q)



Ah I see, p=5 and q=1 (for the positive factors of 5), then after subbing etc you get the 1/30 and 1/6. Sweet, thanks =D
Oh...okay
 

Finx

Member
Joined
Mar 29, 2008
Messages
375
Gender
Male
HSC
2009
Er, whoops, the last line there should be 1/pq

My bad ._.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top