You didnt have to use the A = absinC formula, but yeah they end up crossing out.For the A/A1 question, I used the A=absinC formula and used angle D as C since it was common and they crossed each other out. Is that right? :S
Yeah I did that for the second bit. I used the formula for the first bitYou didnt have to use the A = absinC formula, but yeah they end up crossing out.
you just had to rearrange it so that rt A1 and rt A2 are the subjects of their own equations eg. ( rt A1 = x*rt A/(x+y) )
and then when you add both rt A1 and A2 they cross out to equal rt A
btw rt = square root
Yeah, that's what I got, although after walking out of the exam.btw was the coordinates of P (1/2 , e)?
LolYeah, that's what I got, although after walking out of the exam.
Kept substituting the gradient instead of the full equation and getting:
2 = 1
I don't know what I was thinking...
I'm bitter. Not sure that it should've been worth 3 marks, it was fairly straightforward.