General Thoughts: Physics (2 Viewers)

[kawaiipotato]

Anyone got q21? The height of the wall? I found grqdient of line and subbed into y = ut +1/2 a_y t^2 where u = 0 and t = gradient. Lol dunno if its correct

 

[TQuadded]

Anyone got q21? The height of the wall? I found grqdient of line and subbed into y = ut +1/2 a_y t^2 where u = 0 and t = gradient. Lol dunno if its correct

Pretty sure it's incorrect, but I did it anyway.

 

[IamKirby]

It's correct, gradient is sx/ux which gives time, then you can sub it into sy = 1/2at^2


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[knightus10]

Anyone got q21? The height of the wall? I found grqdient of line and subbed into y = ut +1/2 a_y t^2 where u = 0 and t = gradient. Lol dunno if its correct

I got 2.5 metres

 

[MatISrandom]

can someone post the 2015 physics paper thanks!!

 

[TQuadded]

It's correct, gradient is sx/id which gives time, then you can sub it into sy = 1/2at^2


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Sweet. I was put off by a lot of the marks given - I feel like it was a very generous exam.

 

[IamKirby]

Sweet. I was put off by a lot of the marks given - I feel like it was a very generous exam.

I felt like it was pretty easy except for 1 or 2 questions but I made a lot of stupid errors I think because I just found that it look really long so I didn't have time to check.


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[kawaiipotato]

It's correct, gradient is sx/ux which gives time, then you can sub it into sy = 1/2at^2


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Ah cool. What was the numerical value? I think i remember it being 4. Something?

 

[IamKirby]

Ah cool. What was the numerical value? I think i remember it being 4. Something?

Well I got 2.5 but not sure if it's right.


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[kawaiipotato]

Well I got 2.5 but not sure if it's right.


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My gradient was like 0.86

 

[IamKirby]

My gradient was like 0.86

Mine was whatever gives 2.5


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[malcolm21]

did your line of best fit start from 0?

 

[IamKirby]

did your line of best fit start from 0?

Yeah I had it as that, not too sure whether it's correct. Also had an outlier that I didn't include.


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[BillKyriakos]

Didn't you just have to use the Vertical displacement formula? I got 2.5m as well

 

[CookieMan999]

did your line of best fit start from 0?

i did it from first value to last and not including an outlier

brb witcher 3

 

[malcolm21]

i did it from first value to last and not including an outlier

brb witcher 3

mine excluded the outlier but it didnt touch the first or last value lol, it was in the middle of them and started at 0,0

 

[IamKirby]

Didn't you just have to use the Vertical displacement formula? I got 2.5m as well

Using the given data or the line of best fit?


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[BillKyriakos]

Using the given data or the line of best fit?


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I used the data. More specifically, the horizontal displacement and the velocity to find the time and then subbed that into the vertical displacement formula. Maybe I switched off at that stage but yeah that's what I did

 

[IamKirby]

I used the data. More specifically, the horizontal displacement and the velocity to find the time and then subbed that into the vertical displacement formula. Maybe I switched off at that stage but yeah that's what I did

That's right but I think they wanted us to use the gradient of our line of best fit because it's more accurate or something but not sure. Either way I got 2.5 because my line passed through the final point anyway.


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[BillKyriakos]

Oh, well I guess if we got the same answer then both ways are correct.