Hmmm funky graph (1 Viewer)

[lfc_reds2003]

dunno if 3/4 unit but hey the graph is:

y= arc cos [sqrt(x^2 -1)]

 

[chooette]

I personally like the graph for 4 x^2 y^2 = x^2 + y^2

comes out with 4 parts and a dot at (0,0)

 

[blackfriday]

try tan(e^x). now that graph is so cool.

wow we're all so sad

 

[Estel]

The standard graphing calc on Mac OS 9.x has some pretty good demo graphs that look like 3D landscapes

 

[Trev]

The standard graphing calc on Mac OS 9.x has some pretty good demo graphs that look like 3D landscapes

Such as?
(I would like to know so I can plot them and see what you're talking about!) :uhhuh:

 

[Trev]

Damn Graphmatica, I can never seem to input the equation properly.
How would you input what chooette said?
"4 x^2 y^2 = x^2 + y^2"

 

[Trebla]

I hate to sound immature, but a lot of people like a positive absolute value graph bouncing off the vertex of a narrow concave down parabola, which cuts the x axis only at either negative x values or positive x values. I hate to sound immature but what does it remind you of?
If you don't see it, try graph the following:
y = |x - 2| + 2 and y = - (x - 2)² + 2
What do you see?

 

[Slidey]

Damn Graphmatica, I can never seem to input the equation properly.
How would you input what chooette said?
"4 x^2 y^2 = x^2 + y^2"

Input: 4x^2y^2=x^2+y^2

For:

arc cos [sqrt(x^2 -1)]

First draw sqrt(x^2-1)

Then draw somewhere else the graph of arccos(x).

Now apply the features of sqrt(x^2-1) to arccos(x).

Since the domain of sqrt(x^2-1) is x<=-1 and x>=1, but the domain of arccos(x) is -1<=x<=1, it isn't hard to see that the graph arccos(sqrt(x^2-1)) is comprised of 2 points merely.

 

[Trev]

What does 'arc' mean again? I have a goldfish memory haha.

 

[rama_v]

arc means the inverse function like arcsin is sin^-1 its just to differentiate it from cosec

 

[Trev]

arc means the inverse function like arcsin is sin^-1 its just to differentiate it from cosec

Ahk thanx all understood.

 

[FinalFantasy]

I personally like the graph for 4 x^2 y^2 = x^2 + y^2

comes out with 4 parts and a dot at (0,0)

hey ur avatar looks very evil