K
kleenextissues1
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I cant even remember my answers to shit lol... but the (sqrt( 20^2 + 9^2) x f)/t sounds familiar
Great minds think alikeFor the escalator, Power = W/t
W= change in PE + KE
So in this case W = PE
Hence Power = mgh/25 (25 seconds was the time.)
Weight was 115, height was 9, use 10 for g.
P = 115x9x10/25
=414
As for the Amps one I'm really not sure...
I think R was 800 ohms, 2 was what I used for V so,
2=Ix800
I = 2/800
=2.5x10-3 or 0.0025
x10-3 is milli, so 2.5mA I think...
Sounds familiar man, not sure thoughWhat did you guys get for the reaction in the truss and the force in member x.
I got, reaction a= 14.1 force in x = 15.86(not 100%) but.
+1, but I accidentally added ke, because I thought the person was moving, but oh well, I'll still get a mark.Nope, just the change in GPE. I am 100% sure of it.
devo!+1, but I accidentally added ke, because I thought the person was moving, but oh well, I'll still get a mark.
+1 I defo got a, can't remember my value for member XSounds familiar man, not sure though
Exactly what I gotSome random answers off the top of my head
For the one with escalator with 115kg on it, answer was 414W I think.
I got 40 something mm for the extension of the cable in the last question.
Question about the current in the circuit with the lightbulb I got 2.5mA.
Any of these answers ring a bell with anyone else?
That is what I got.Some random answers off the top of my head
For the one with escalator with 115kg on it, answer was 414W I think.
I got 40 something mm for the extension of the cable in the last question.
Question about the current in the circuit with the lightbulb I got 2.5mA.
Any of these answers ring a bell with anyone else?
i had exact the same problems as you brooJesus christ.... did anyone else fail hardcore at the drawings.. and ESPECIALLY the shear and bending moment diagrams? wtf was that? the force was like on a non given distance..
Macrostructure of laminates? are you fucking kidding me?
i got 20 aswellYeh most are right, but how did u get 2.5mA, I somehow got 20mA
Ah I knew there was something to do with the voltage drop... However, the voltage went from 18 to 2, making the voltage drop 16. So from what you've written that still makes V = 2? Unless you just mistyped it or something.For the voltage question I'm pretty sure its 20mA.
Voltage = 18V
Voltage drop(voltage lost in circuit) = 2V
So voltage = 16v
V= IR
16=I*800
I = 0.02A = 20mA
Similar to question18 in 2009 hsc exam
Nah mate, 2.5mAFor the voltage question I'm pretty sure its 20mA.
Voltage = 18V
Voltage drop(voltage lost in circuit) = 2V
So voltage = 16v
V= IR
16=I*800
I = 0.02A = 20mA
Similar to question18 in 2009 hsc exam
hmm for X...cant believe people r saying this exam was easy. fucken hardest engineering one ive ever come across...
did anyone get like 23 or so KN for member X. In compression as well?
The only maths that fucked me over was that bloody bicycle...