SpiralFlex
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Re: MX2 Integration Marathon
U power 6 substitution is faster
U power 6 substitution is faster
The solution I got had ln in it.K I did that and got int(6x^3+6-(1/((x-0.5)^2+0.75)))
Final result is (3x^4)/2+6x-(2/sqrt3).tan^-1((2x-1)/sqrt3)
That right?
This is what I was aiming at.U power 6 substitution is faster
yeah i guess but it's easier to split the numerator by long division or inspection. could definitely come up in 3u and maybe even 2upeople utilised integration by parts at my school to solve it so yea..
Could you show me how u did it then? I am wrong haha.The solution I got had ln in it.
This is what I was aiming at.
Alternatively you could let x=tan@ and resolve it to the same thing that sy gotAlternatively you could have rationalised the numerator and put x^2=sin@.
Could you show me how u did it then? I am wrong haha.
Ahhh yes I see where I went wrong. Thanks
From the expanded version of the product rule for differentiating a product of three functions (y=uvw becomes y'=uvw'+uv'w+u'vw), the answer is arcsinx.arccosx.arctanx
This isn't correct. You should end up with a secant cubed if you use some substitution.Is the answer:
?????
By using s^2+c^2 = 1, then multiplying top and bottom by secant squaredintegrate from pi/2 to 0, 1/(2sin^x + cos^2x),