• Best of luck to the class of 2024 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page
MedVision ad

HSC 2012 MX2 Marathon (archive) (1 Viewer)

Joined
Sep 20, 2010
Messages
2,225
Gender
Undisclosed
HSC
2012
Re: 2012 HSC MX2 Marathon



I've spared the messy algebra...

The addition/product of roots would work also I think.
 
Last edited:

Inference

New Member
Joined
May 1, 2012
Messages
5
Gender
Undisclosed
HSC
N/A
Re: 2012 HSC MX2 Marathon

Why don't we add some pure maths questions in here,

here's a fave one of mine, combinatorics

A permutation of the set where is a positive integer, is said to have property if for at least one . Show that, for each , there are more permutations with property than without.

Hint: Indicator functions will help, and think about counting sets
 

Carrotsticks

Retired
Joined
Jun 29, 2009
Messages
9,494
Gender
Undisclosed
HSC
N/A
Re: 2012 HSC MX2 Marathon

Why don't we add some pure maths questions in here,

here's a fave one of mine, combinatorics

A permutation of the set where is a positive integer, is said to have property if for at least one . Show that, for each , there are more permutations with property than without.

Hint: Indicator functions will help, and think about counting sets
If you want some Pure Maths questions unrelated to the HSC, then feel free to make your own thread in the 'Extracurricular Maths' section: http://community.boredofstudies.org/forumdisplay.php?f=238
 

Inference

New Member
Joined
May 1, 2012
Messages
5
Gender
Undisclosed
HSC
N/A
Re: 2012 HSC MX2 Marathon

Thanks, but it is related to the HSC albeit a fair extension.

You guys do combinatorics in the HSC right? The above question can be solved purely combinatorially.
 

barbernator

Active Member
Joined
Sep 13, 2010
Messages
1,439
Gender
Male
HSC
2012
Re: 2012 HSC MX2 Marathon

Thanks, but it is related to the HSC albeit a fair extension.

You guys do combinatorics in the HSC right? The above question can be solved purely combinatorially.
we learn factorial notation for combs and perms and how to apply them, that is about all lol.
 

Inference

New Member
Joined
May 1, 2012
Messages
5
Gender
Undisclosed
HSC
N/A
Re: 2012 HSC MX2 Marathon

Ah right I see, okay I guess it is a fair stretch then, maybe a bit of wishful thinking can lead somewhere ;)
 

httton

Member
Joined
Mar 5, 2011
Messages
51
Gender
Undisclosed
HSC
2012
Re: 2012 HSC MX2 Marathon

Hey guys just two questions

1/ what are some ways to determine whether a question should be done with shells or slices
2/ if I'm given a shape like x^2(6-x^2) find area enclosed in 1st quadrant rotated about the y axis how do I go about it?
 

bleakarcher

Active Member
Joined
Jul 8, 2011
Messages
1,509
Gender
Male
HSC
2013
Re: 2012 HSC MX2 Marathon

^ cylindrical shells would be easier there
 

Carrotsticks

Retired
Joined
Jun 29, 2009
Messages
9,494
Gender
Undisclosed
HSC
N/A
Re: 2012 HSC MX2 Marathon

Hey guys just two questions

1/ what are some ways to determine whether a question should be done with shells or slices
2/ if I'm given a shape like x^2(6-x^2) find area enclosed in 1st quadrant rotated about the y axis how do I go about it?
Generally, rotation around a line parallel to the Y axis is more easily done using Shells.

X axis is more easily done using Slicing.

But of course both will yield correct answers (but one will yield a harder integral than the other).

Example: Rotate the area bounded by the curve y=-x(x-1) and the X axis, around the line x=2.

If you use Slicing, you will need to eventually use the Quadratic formula. and then integrate that expression.
 

httton

Member
Joined
Mar 5, 2011
Messages
51
Gender
Undisclosed
HSC
2012
Re: 2012 HSC MX2 Marathon

haha i went out to have a good think and came back with the same idea!

for the others, essentially try to have your slice correspond to 1 x to 1 y values each
 

seanieg89

Well-Known Member
Joined
Aug 8, 2006
Messages
2,662
Gender
Male
HSC
2007
Re: 2012 HSC MX2 Marathon

When thinking about whether shells or annuli will be more efficient, consider the resulting integrands. There will generally be a sort of inverse relation between our integrands (as we are integrating in perpendicular directions for these two methods), and we prefer to have things like tan(x) in our integrand rather than tan^{-1}(x).
 

Trebla

Administrator
Administrator
Joined
Feb 16, 2005
Messages
8,381
Gender
Male
HSC
2006
Re: 2012 HSC MX2 Marathon

This one might look like it is beyond the course but it can be solved using methods within the scope of Ext2 level.

Suppose that f(x) is an even function. Show that



Hence evaluate

 
Last edited:

Fus Ro Dah

Member
Joined
Dec 16, 2011
Messages
248
Gender
Male
HSC
2013
Re: 2012 HSC MX2 Marathon

This one might look like it is beyond the course but it can be solved using methods within the scope of Ext2 level.

Suppose that f(x) is an even function. Show that



Hence evaluate

First part split the integral as two terms then the integral with the i in it cancels out due to the sine function and we are left with 2x integral of f(x)cos(x). Second part use the property f(x) = f(a-x), add the two integrals, the icos(x) term cancels and the result follows.

I am a bit skeptical regarding this question being within Ext2 level without proper justification because we are taking the Riemann integral of a complex-valued function. It may require justification that it works in this case because is a vector space. Other students might get confused about having an i in the integral.
 

OMGITzJustin

Well-Known Member
Joined
Jun 28, 2010
Messages
1,002
Gender
Male
HSC
N/A
Re: 2012 HSC MX2 Marathon

First part split the integral as two terms then the integral with the i in it cancels out due to the sine function and we are left with 2x integral of f(x)cos(x). Second part use the property f(x) = f(a-x), add the two integrals, the icos(x) term cancels and the result follows.

I am a bit skeptical regarding this question being within Ext2 level without proper justification because we are taking the Riemann integral of a complex-valued function. It may require justification that it works in this case because is a vector space. Other students might get confused about having an i in the integral.
yeah I agree with with you, the question seems like it isnt in the scope of the ext 2 course
 

Trebla

Administrator
Administrator
Joined
Feb 16, 2005
Messages
8,381
Gender
Male
HSC
2006
Re: 2012 HSC MX2 Marathon

Okay made it heaps easier...

Suppose that f(x) is an even function and k is a constant. Show that



Hence evaluate

 
Last edited:

bleakarcher

Active Member
Joined
Jul 8, 2011
Messages
1,509
Gender
Male
HSC
2013
Re: 2012 HSC MX2 Marathon

can you treat 'i' as a constant?
 

seanieg89

Well-Known Member
Joined
Aug 8, 2006
Messages
2,662
Gender
Male
HSC
2007
Re: 2012 HSC MX2 Marathon

Might as well bring this back to life.

Prove that the polynomial



has no real roots. (Where n is a non-negative integer.)
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top