Carrotsticks
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Re: HSC 2013 4U Marathon
Your answer 2ln(2) - 1 is however correct. My method was to determine a set of inequalities which made a 'hyperbolic triangle', then found the area of the triangle either through a non-linear transformation or playing around with a bit of geometry and integration etc.
My mistake Sean, the question was supposed to be an ACUTE ANGLED triangle, but I didn't type out the 'acute angled' part.Hmmm...I got 2*log(2)-1. Are you sure your answer is correct?
Your answer 2ln(2) - 1 is however correct. My method was to determine a set of inequalities which made a 'hyperbolic triangle', then found the area of the triangle either through a non-linear transformation or playing around with a bit of geometry and integration etc.
Read above. Fus Ro Dah is not mistaken, I sent him the correct question privately via PM whereas I typed down the wrong one here on the thread, which is why he acquired his answer. My fault for the typo.What you have worked out is not the answer to the question. Your answer is for forming a right angled triangle. Now I see why the probability is so low.
My typos strike again!This is going to be good.