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HSC 2014 MX2 Marathon (archive) (3 Viewers)

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Tugga

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Re: HSC 2014 4U Marathon

dunjaaa said:
View attachment 30936
Click to expand...
Did it a different way by letting w=x+iy and simplifying z, to get z=i(y/(1-x))=+-i(sqrt((1-x)/(1+x)), which for -1(lessthan)x(lessthan)1 ,draws out the imaginary axis with a hole at origin.

Like your solution better though :p

edit: how do you use less than signs without stuffing up...
 
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Kurosaki

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Re: HSC 2014 4U Marathon

Tugga said:
Did it a different way by letting w=x+iy and simplifying z, to get z=i(y/(1-x))=+-i(sqrt((1-x)/(1+x)), which for -1(lessthan)x(lessthan)1 ,draws out the imaginary axis with a hole at origin.

Like your solution better though :p

edit: how do you use less than signs without stuffing up...
Click to expand...
Do you mean in Latex o_O
You just do <
 
Fizzy_Cyst

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Re: HSC 2014 4U Marathon

Four digits numbers are formed from the digits 1,2,3,4. Each digit is only used once. What is the sum of all the numbers that can be formed?
 
Fizzy_Cyst

Fizzy_Cyst

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Re: HSC 2014 4U Marathon

faisalabdul16 said:
Ruse's multiple choice for trials
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Was it? I got it from Normanhursts trial from this year. It was Q10. Perhaps they used the same paper?

EDIT:

just checked -- a couple of MCQ's the same, but that is it
 
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