Integration Question (1 Viewer)

[Deep Blue]

The answer states that you divided through the square root by x^2 , making it x^3 out front of the square root and then use a substitution where u = 1/x^2, meaning that du = -2/x^3

Is it possible to solve using a trig, then t substitution?

 

[deterministic]

Yes you can do it by trig as well
eg. substitute

 

[AAEldar]

The answer states that you divided through the square root by x^2 , making it x^3 out front of the square root and then use a substitution where u = 1/x^2, meaning that du = -2/x^3

Is it possible to solve using a trig, then t substitution?

Factorizing the from under the square root is so much nicer though.

 

[cutemouse]

I prefer the substitution x=1/u for these types of problems... But that's just me.