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Just a quickie (1 Viewer)

ngai

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mojako said:
sqrt(x) has vertical tangent x=0
log(x)... hmm... this one.. is a bit strange hahaha... I dont think this has an endpoint... (with my definition of endpoint anyway)
oh u meant finite domain but doenst satisfy ur other conditions
 

Xayma

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mojako said:
But.. how can someone be expected to know that the two reasons are these two... well he can guess.. trying to make up two reasons because the Q asks for 2 :D
Well the dividing by 0 is obvious.

|x|>0 (since x≠0)
∴ if x>0, |x|/x=1
if x<0, |x|/x=-x/x=-1 (since |x|=-x, if x<0)

ok?
 

mojako

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ngai said:
oh u meant finite domain but doenst satisfy ur other conditions
probably..
u need to read between the lines..
draw meaning from the not-obvious..


ok I admit defeat :p
 

mojako

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Xayma said:
Well the dividing by 0 is obvious.

|x|>0 (since x&ne;0)
&there4; if x>0, |x|/x=1
if x<0, |x|/x=-x/x=-1 (since |x|=-x, if x<0)

ok?
but how do u know it's classified as a "reason"?
Is this on the syllabus or textbook somewhere?
 

Xayma

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Pfft no, but it is a reason it is a piece graph, two straight unjoined lines seperating different critera.

y=|x|/x is the same graph as y=-1 x<0, y=1 x>0
 

Li0n

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Xayma said:
Pfft no, but it is a reason it is a piece graph, two straight unjoined lines seperating different critera.

y=|x|/x is the same graph as y=-1 x<0, y=1 x>0
i agree with that
 

Raginsheep

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It was some question my friend asked me. Its supposed to be Yr11 3U work so no tricky stuff needed.
 

Archman

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haven't seen anything tricky yet.
apart from invisi text
 

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