Multiple Choice (1 Viewer)

JustinLy007

New Member
Joined
Feb 13, 2012
Messages
1
Gender
Male
HSC
2013
I think 5 is D..... Due to itself being a transuaranic element non existent... so exisiting with element 102 rather than element 16 itself?
 

leesh95

Member
Joined
Nov 7, 2011
Messages
487
Gender
Undisclosed
HSC
2013
I think 5 is D..... Due to itself being a transuaranic element non existent... so exisiting with element 102 rather than element 16 itself?
It asked what group the element would be in though not the period
 

AfkForSoR

New Member
Joined
Oct 30, 2013
Messages
11
Gender
Male
HSC
2013
Equal. The degree of ionisation won't affect the volume needed, the pH of the titration at the equivalence point just won't be 7.
But a weak acid does not completely ionise, so it will keep ionising as the titration begins so basically when the base things it has neutralised all of the acid, it will ionise another H+ for the base to ionise :. it would require more volume than a strong acid which has a set amount of H+ in the beginning of the titration. I'm like 98% sure, but guess we'll have to see :)
 

Recondit

ヽ(" `Д´)ノ
Joined
May 3, 2012
Messages
400
Gender
Male
HSC
2013
16/20 -- dont know why but I thought acetic acid was triprotic, [18] was a bad silly mistake from me
 

AfkForSoR

New Member
Joined
Oct 30, 2013
Messages
11
Gender
Male
HSC
2013
15 is C, it was 10 and 990 you had to read carefully second column was "Volume ADDED" so you add to the original sample 990 + 10 = 1000. and use c1v1=c2v2
 

AfkForSoR

New Member
Joined
Oct 30, 2013
Messages
11
Gender
Male
HSC
2013
question 5 correct answer is d because anything after 92 atomic number is transuranic 116 and 112 are both transuranic therefore answer is d
It said which period the element was in, and it was in the same period as the element "S-16"
 

superSAIyan2

Member
Joined
Apr 18, 2012
Messages
320
Gender
Male
HSC
2013
fwar nice recondit!!
what you get? 12? :p

was it just me or did the first 7questions (except2) seem like they could be in the year 8or9 chem comp. Especialy question 4.
 
Last edited:

babberz

New Member
Joined
Jan 28, 2013
Messages
28
Gender
Undisclosed
HSC
2013
15 is C, it was 10 and 990 you had to read carefully second column was "Volume ADDED" so you add to the original sample 990 + 10 = 1000. and use c1v1=c2v2
wait, how'd u get this? what values did you use for c1 and c1 3M hcl was diluted to 5M hcl
 

Menomaths

Exaı̸̸̸̸̸̸̸̸lted Member
Joined
Jul 9, 2013
Messages
2,373
Gender
Male
HSC
2013
wait, how'd u get this? what values did you use for c1 and c1 3M hcl was diluted to 5M hcl
There's a dot point that says 'identify that a change a change of pH is 10 fold' or something like that so you can work out it has to be 100 times more diluted (don't remember the question but that's how I derived the 100)
 

babberz

New Member
Joined
Jan 28, 2013
Messages
28
Gender
Undisclosed
HSC
2013
There's a dot point that says 'identify that a change a change of pH is 10 fold' or something like that so you can work out it has to be 100 times more diluted (don't remember the question but that's how I derived the 100)
oh yeh i got it now, damn
 

nifkeh

Member
Joined
May 29, 2012
Messages
383
Gender
Female
HSC
2013
For 17 answer is greater than the volume as strong acids completely ionise and weak do not so it will continue to ionise as it is being titrated, requiring more volume to neutralise than the strong acid (i am 100% sure)
It doesn't I did the 2011 multiple choice Q about titration volumes and it's still the same amount of acid (despite weak or strong)
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top