need help URGENTLY!! (1 Viewer)

Pace_T

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Integrate:
S(cosec^2(x))dx

A = -cot(x) + c

S(cosec(x)cot(x))dx

A = -cosec(x) + c

S(sec(x)tan(x))dx

A = sec(x) + c

These are common rules i think, but im pretty sure my teacher will put 1 of them in the halfy tomorrow!!! (unless these don't have to be proven? but i cannt be sure though). i know ive been asking alot of q's recently but my half yearly is just coming up, ill help as much as i can in return!
somone please help!! thank you!
:D
 

richz

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why dont u just remember them??? even u said they are common rules.... :rollyeyes:
 

KFunk

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Pace_T said:
Integrate:
S(cosec^2(x))dx

A = -cot(x) + c

S(cosec(x)cot(x))dx

A = -cosec(x) + c

S(sec(x)tan(x))dx

A = sec(x) + c

These are common rules i think, but im pretty sure my teacher will put 1 of them in the halfy tomorrow!!! (unless these don't have to be proven? but i cannt be sure though). i know ive been asking alot of q's recently but my half yearly is just coming up, ill help as much as i can in return!
somone please help!! thank you!
:D
I assume you want to know how to prove them? Working backwards:

∫ secx.tanx dx
= &int; (cosx)<sup>-2</sup>.sinx dx let u=cosx ---> du = -sinxdx
= - &int; u<sup>-2</sup> du
= -(-1/u) = 1/cosx = secx + c

&int; cosecx.cotx dx
= &int; (sinx)<sup>-2</sup>.cosx dx let u=sinx ---> du=cosxdx
=&int; u<sup>-2</sup> du
= -1/u = -cosecx +c
 

KFunk

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&int; cosec<sup>2</sup>x dx
= &int; cot<sup>2</sup>x.sec<sup>2</sup>x dx
= &int; (tanx)<sup>-2</sup>.sec<sup>2</sup>x dx
let u = tanx ---> du = sec<sup>2</sup>xdx

= &int; u<sup>-2</sup> du
= -1/u = -1/tanx = -cotx +c
 

Slidey

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This is 4unit, just so you know, Pace.
 

Pace_T

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thanks all, you people are so helpful :D:D
oh, i *think* they are common rules, but none the less, my teacher is a nutcase, he'll put in any sorts of questions cause he's a gaybo.
LOL
thanks
 

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