Need help with this integration Q ! (1 Viewer)

[ScarFace93]

how do you integrate this ?

1/(e^2x + e^x)

thanks

 

[nikkifc]

how do you integrate this ?

1/(e^2x + e^x)

thanks

Let u=e^x
du/dx=e^x = u

 

[shaon0]

Let u=e^x
du/dx=e^x = u

Thats incorrect. Divide by e^2x.
I=S dx/e^2x+e^x
= -S e^-x.-e^-x/(1+e^-x) dx
= -S u du/(1+u)
= S 1/(u+1) -1 du
= ln(u+1)-u +C
= ln(e^-x+1)-e^-x+C

 

[nikkifc]

Thats incorrect. Divide by e^2x.

Whoops. I shouldn't do maths after a long day. haha

 

[shaon0]

Whoops. I shouldn't do maths after a long day. haha

Yeah, nw.

 

[fullonoob]

wow nice question, even had partial fractions in there, great job shaono