PARAMRETICS: Chord of Contact. (1 Viewer)

[Divinity_]

Parametrics is a killer. I don't know how to derive the chord of contact: x x0 = 2a ( y + y0 )

 

[M@ster P]

yeh it's quite difficult deriving things, although deriving ur mum last night was a piece of cake, especially her chord of contact with my penis

lmao, sad

 

[tommykins]

wow that was so bad.

 

[jet]

Well, there's two ways - One which is quite quick but REALLY hard to understand, or one which is quite a bit longer. I have a powerpoint on parametrics I might post up - I gave a presentation to the 3 unit maths class this year, however its not on this computer. I'll do it tomorrow.

 

[untouchablecuz]

Parametrics is a killer. I don't know how to derive the chord of contact: x x0 = 2a ( y + y0 )

note that M and N lie on the parabola

 

[bored.of.u]

 

[cutemouse]

I believe that's the only equation you can memorise and not have to be able to derive in the parametrics locus topic.

 

[jet]

Here's the ppt. I know it's bit but it's got everything, including both proofs of chord of contact.
I spent a lot of time trying to explain the first method. I got through to most people, but if you don't get it, use the second method below.

Here, 'They' refers to the two tangents.

 

[kwabon]

its nuts deriving it in parametric form,
will have to use conversion of sum to products of trigonometric ratios.

 

[scardizzle]

our teacher calls the derivation of the one without paramaters the sleight of hand trick