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point of inflexion (2 Viewers)

joshlols

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Re: 回复: Re: point of inflexion

Timothy.Siu said:
nah its not e.g. y=x^4 doesn't have one
Thank you captian obvious, because concavity doesn't change.
 

tommykins

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回复: Re: point of inflexion

dolbinau said:
Is there ever a case when an x value of F''(x)=0 is not an inflexion point?
i'm assuming f''(x-1) is positive/negative and f''(x+1) is positive/negative respectively.

no change in concavity = a normal point?
 

dolbinau

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Re: 回复: Re: point of inflexion

joshlols said:
Thank you captian obvious, because concavity doesn't change.
His point was you have to test.
 

danz90

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Re: 回复: Re: point of inflexion

In the Mathematics HSC Exam.. if you are asked to "Find any points of inflexion" for 1 mark... would you also have to test the point or prove its a pt of inflexion, to gain the 1 mark?
 

Timothy.Siu

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Re: 回复: Re: point of inflexion

danz90 said:
In the Mathematics HSC Exam.. if you are asked to "Find any points of inflexion" for 1 mark... would you also have to test the point or prove its a pt of inflexion, to gain the 1 mark?
yes
well, maybe not but how will u know if it is or not? i'm not willing to take a 50% chance for 1 mark (u know wat i mean)
 

dolbinau

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Re: 回复: Re: point of inflexion

danz90 said:
In the Mathematics HSC Exam.. if you are asked to "Find any points of inflexion" for 1 mark... would you also have to test the point or prove its a pt of inflexion, to gain the 1 mark?
In answers for HSC exams I have they always test. It only takes 5 seconds and you could easily just test one side for the concavity then fill the rest in as you know what it will be.
 

tommykins

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回复: Re: 回复: Re: point of inflexion

Graceofgod said:
I think I must have missed some sarcasm or misunderstood your question...
You're saying since f''[5] < 0 and f''[3] > 0, then f''[4] = 0 which is not true.

What about 4.3? 3.4? 3.2? 4.5678685453 ?

You have to solve the equation for f''[x], you can't simply assume that at x = 4, there is an inflection point.
 

18836165

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Re: 回复: Re: point of inflexion

dolbinau said:
In answers for HSC exams I have they always test. It only takes 5 seconds and you could easily just test one side for the concavity then fill the rest in as you know what it will be.
Assuming it is a point of inflexion.

Just simply think about whether it will be positive or negative, don't actually find an exact value unless you can't work it out easily.
 

mick135

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Arithela said:
what is the difference between a point of inflexion and a horizontal point of inflexion? if there is a difference, when do we use them? thanks
I don't know if this is still your question or not - the thread is 4 pages long now. but i can't be bothered reading all 4 pages of gossip so i'm just gonna answer this question.

Definition of Differentiating a function of any kind. Finding the first derivative gives the equation of the "tangent" to the graph - which you sub in particular x and y values to find that particular tangent to each graph.

so a point of inflexion is where the derivative is equal to zero and concavity changes.
ie: F'(X) = 0 or y'=0 (just a stationary point basically)
a horizontal point of inflexion is where the tangent is flat
so when you find the 2nd derivative or F"(X), they = 0

and listen to tommykins = that guy is a brain and a half.
 

Graceofgod

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Re: 回复: Re: 回复: Re: point of inflexion

tommykins said:
You're saying since f''[5] < 0 and f''[3] > 0, then f''[4] = 0 which is not true.

What about 4.3? 3.4? 3.2? 4.5678685453 ?

You have to solve the equation for f''[x], you can't simply assume that at x = 4, there is an inflection point.
Ah good, so it was you who missed what I meant.

We are talking about proving that it is a point of inflexion.

If you find that f"(4) = 0, then check f"(3) and f"(5), you can see if it is actually a point of inflexion.

My question was whether or not you could get away with just saying

f"(3) > 0 and f"(5) < 0 without showing working.
 

tommykins

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回复: Re: 回复: Re: 回复: Re: point of inflexion

Graceofgod said:
Ah good, so it was you who missed what I meant.

We are talking about proving that it is a point of inflexion.

If you find that f"(4) = 0, then check f"(3) and f"(5), you can see if it is actually a point of inflexion.

My question was whether or not you could get away with just saying

f"(3) > 0 and f"(5) < 0 without showing working.
if that's the case, then yes, you can state f''[3] < 0 and f''[5] > 0 .'. at x = 4 point of inflection as concavity changes.

sorry for the misunderstanding.
 

Graceofgod

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Re: 回复: Re: 回复: Re: 回复: Re: point of inflexion

tommykins said:
if that's the case, then yes, you can state f''[3] < 0 and f''[5] > 0 .'. at x = 4 point of inflection as concavity changes.

sorry for the misunderstanding.
Its cool :) I got my answer in the end. Thanks.
 

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