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Preliminary mathematics marathon (2 Viewers)

AAEldar

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Yea..why did you repear so many times?

It is right however
My bad, it screwed up when I first tried to put it in, had url in there for some reason :S Fixed it now :)

Good to know it's right, was confused for a sec there hahaha.
 

hscishard

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Can someone do Q23 Chp 14B in Cambridge 3unit, Year 11.
Can't type this question up.
I don't know how to find the perimeter of the bigger hexagon.
 

Drongoski

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hscishard - pl type out question at leat for benefit of readers


 
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Insert the link between
.

Alternatively, just click "Go Advanced" and click on the insert image button.
 
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I don't want this thread to die :(

New Question:

A piece of wire is 70 cm long. One section is bent into an equilateral triangle and the other into a rectangle that is three times as long as it is wide. Find the lengths of the two pieces of wire if the sum of the areas of the two shapes is a minimum.
 

hscishard

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I don't want this thread to die :(

New Question:

A piece of wire is 70 cm long. One section is bent into an equilateral triangle and the other into a rectangle that is three times as long as it is wide. Find the lengths of the two pieces of wire if the sum of the areas of the two shapes is a minimum.
Wth..I got 34.54 and 35.46.
 
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Then make it into a general quadratic expression and find the minimum value of the parabola.
 

hscishard

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Then make it into a general quadratic expression and find the minimum value of the parabola.
I did it in a similar way. Except I let x = perimeter of triangle.
Therefore each side was x/3.

Not sure which is more complicated.
But I didn't get

From the way you did it the 4 should be a 2.

I somehow got this for that.


EDIT: Wait no I didn't I had 3(70-x)^2/64. ?????
 
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