T Teoh Member Joined Feb 8, 2004 Messages 150 Aug 11, 2004 #1 This is probably more a 3 unit question, but probability isn't computing Sophia, Gabriel and Elizabeth take their driving test. The chances that they pass are 1/2, 5/8 and 3/4 respectively. Find the probability that exactly one of the three passes.
This is probably more a 3 unit question, but probability isn't computing Sophia, Gabriel and Elizabeth take their driving test. The chances that they pass are 1/2, 5/8 and 3/4 respectively. Find the probability that exactly one of the three passes.
withoutaface Premium Member Joined Jul 14, 2004 Messages 15,098 Gender Male HSC 2004 Aug 11, 2004 #2 1/2*3/8*1/4+1/2*5/8*1/4+1/2*3/8*3/4
cj_bridle Member Joined Jun 23, 2004 Messages 169 Gender Male HSC 2004 Aug 11, 2004 #3 (1/2 x 3/8 x 1/4) + (1/2 x 5/8 x 1/4) + (1/2 x 3/8 x 3/4) = [edit] 17/64 taking the probabilities of one passing then the other 2 failing.. then changing who passes.. then adding those 3 together. [edit] beat me biatch [edit2] sorry my calculating was a bit off the algorithm is right answer is = 17/64 Last edited: Aug 11, 2004
(1/2 x 3/8 x 1/4) + (1/2 x 5/8 x 1/4) + (1/2 x 3/8 x 3/4) = [edit] 17/64 taking the probabilities of one passing then the other 2 failing.. then changing who passes.. then adding those 3 together. [edit] beat me biatch [edit2] sorry my calculating was a bit off the algorithm is right answer is = 17/64
cj_bridle Member Joined Jun 23, 2004 Messages 169 Gender Male HSC 2004 Aug 11, 2004 #5 sorry my dodgy calculating was off.. the algorithm is right.. just calculated wrong.. that does give 17/64
sorry my dodgy calculating was off.. the algorithm is right.. just calculated wrong.. that does give 17/64