This is how i see it.
Elements at the top of the reduction table will oxidise over sumthing at the bottom.
ie. an element at the top of the table will oxidise more easily.
ie. the element is more reactive.
since Pb oxidises (negative electrode) and X reduces (postive electrode). this means that Pb Oxidises more easily than X.
and also since Z and Y oxidise when in a cell with Pb, they are more reactive.
ie they are preferentially oxidised over Pb.
ie. they are easiER (increasing ease) to oxidise than Pb.
So the answer must be D.
Understand ChelseaFan?
Elements at the top of the reduction table will oxidise over sumthing at the bottom.
ie. an element at the top of the table will oxidise more easily.
ie. the element is more reactive.
since Pb oxidises (negative electrode) and X reduces (postive electrode). this means that Pb Oxidises more easily than X.
and also since Z and Y oxidise when in a cell with Pb, they are more reactive.
ie they are preferentially oxidised over Pb.
ie. they are easiER (increasing ease) to oxidise than Pb.
So the answer must be D.
Understand ChelseaFan?