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raw marks for a band 6? (1 Viewer)

Cookie182

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110 + seems doable for me (my trial result) but it will be dependent on my timing- q 10 is a bitch as always and i often screw probability.
 

mc88

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I just 86.6% in a practice HSC test...will this make it to a band 6?
 

572SS

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imprsiv said:
96-99/120 shuld give u a band 6

75/120 will be around a low band 5 aligned

gl
75/120 a band 5???????

can anyone put truth behind this claim?
 

forevaunited

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Isn't it all relative to how the state goes? If its a really easy test and a high percentage of people get above 95 or 100, wont that mean they have to scale/align/(i dont know the correct terminology) down? hmm im not really sure on that.

and whoever said that question 10 is a bitch - i second your statement. i very rarely get them. but the thing is most of em just require incredibly long calculations and differentiating something that takes up a whole page. extremely boring and time-consuming maths - makes me angry.
 

morganforrest

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forevaunited said:
Isn't it all relative to how the state goes? If its a really easy test and a high percentage of people get above 95 or 100, wont that mean they have to scale/align/(i dont know the correct terminology) down? hmm im not really sure on that.

and whoever said that question 10 is a bitch - i second your statement. i very rarely get them. but the thing is most of em just require incredibly long calculations and differentiating something that takes up a whole page. extremely boring and time-consuming maths - makes me angry.
Question isn't really that bad...it ust requires a bit of intuitive thinking that isn't usually honed in 2unit maths....MX1 people will find it easier because we're used to having to think outside the box to answer a question. Question 10 is just a lock that, once you find the key, falls apart quite easily

Just look at what they give you, think about where your trying to go with it if it's a proof and look for holes in ur knowledge....that hole will need to be filled with some proof or number or whatever and the whole thing will work
 

samuel slack

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Meh I fail at maths. I've been practicing past papers, and getting around 60/120 everytime. Hopefully I'll get scaled up a bit. I can usually get a couple of marks out of a question 9 or 10 from the first couple of parts, but after that I just get lost and confused... and plus it takes so long to do them. I dont think I'll have the time in the exam. Question 1-7 for a pass, ftw.
 

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If you're Band 5 or 6 material you could solve this:

The section of the curve y = rx/h (r and h are constants), between x = 0 and x = h rotated about the x-axis.
Show that finding the volume of the resulting solid revolution gives the formula for the volume of the cone.

EDIT: Solutions: http://tinyurl.com/25u2ke
 
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helper

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Forbidden. said:
Source (Primary): Board of Studies - Examination Statistics 1988-2000
Source (Secondary): Excel Fast Track - 50 HSC EXAM TIPS - MATHS (2UNIT) - Jeff Geha
Totally irrelevant as the system changed in 2000. Before that the mean and SD was kept the same each year in each subject.
 

samuel slack

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mkay. the volume of a cone is 1/3 pi r^2h right?
Well. This is what I ended up with, its definitely gone wrong somewhere.

pi [(2rh)^3)/3h]... where'd I go wrong?
 

Forbidden.

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samuel slack said:
mkay. the volume of a cone is 1/3 pi r^2h right?
Well. This is what I ended up with, its definitely gone wrong somewhere.

pi [(2rh)^3)/3h]... where'd I go wrong?
I bet the constants are the case of this.

Let's play let's pretend:

If rx/h = 2x, then if you square it then you get r2/h2 . x2 or 4x2 in the game of let's pretend.

Then when you integrate you get r2/h2 . x3/3 = r2x3/3h2

Along the way then let's pretend the interval h is 2.
h is a constant.
You shove the constant into the variable making it a constant.
So the constant can be divided by a constant hence. h3/h2 = h

= r2/h2 . (h)3
= r2h3/3h2
= r2h/3

or ...

= r2/(2)2 . (2)3
= r2(2)3/3(2)2
= 2r2/3
 

morganforrest

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Yep easy....square top and bottom...take r^2/h^2 out the front of the integral, since these are constants, as well as the pi u multiply by since its a volume of revolution....integrate x^2 expand, you get 1/3pi^3....then multiply it by the pi.r^2/h^2 and simplify to get 1/3.pi.r^2.h( formula for volume of a cone)

mmkthxbai :wave:

But I <3 integral calculus...sequences and series is my bitch :burn: :bomb:
 
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morganforrest said:
Yep easy....square top and bottom...take r^2/h^2 out the front of the integral, since these are constants, as well as the pi u multiply by since its a volume of revolution....integrate x^2 expand, you get 1/3pi^3....then multiply it by the pi.r^2/h^2 and simplify to get 1/3.pi.r^2.h( formula for volume of a cone)

mmkthxbai :wave:

But I <3 integral calculus...sequences and series is my bitch :burn: :bomb:
How we think alike ! :eek:
 

samuel slack

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Okay. So before I do any integrating constant have to be brought outside the integral? Very nice... I get it.
 

slasher3689

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Eh, that wasnt too hard... I got right up the very last part and wondered why my answer was slightly wrong, and I relised that I forgot to get rid of the r that got timesd by 0. If that even makes sense...

To be honest that seems more like a question 7 or 8 to me...
 

morganforrest

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samuel slack said:
Okay. So before I do any integrating constant have to be brought outside the integral? Very nice... I get it.
They don't HAVE to as such, but it makes it a whole lot easier to see what you're meant to integrate and what you just leave....some people would make the mistake of integrating the r and h so bringing it out the front just keeps the algebra/calculus simpler
 

samuel slack

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fair enough... urgh. I can't wait until maths is over... If i can somehow fluke a band 4 I'd be completely stoked...
 

mitchmacca22

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the way my teachers always tell me is if you can get over 100/120 you will def get a band 6. it also depends on your rank, as in your assessment mark they sent in, and how good everyone goes
 

Armenikum

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Boo probability!

Forbidden - band 6 student?

Maybe band 5 lol, cmon man!
 

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