The sample at Site 1 is just after the sewage plant discharge, this would increase the BOD and E. Coli, for obvious reasons.Darrow said:For 12 I got B
Explain why it is A
But there isn't even the option of Site 3 being the mine?Kearnzo said:The sample at Site 1 is just after the sewage plant discharge, this would increase the BOD and E. Coli, for obvious reasons.
This would disperse by the Estuary sample.
The TDS at site 3 is very high, this would occurs because of copper mine discharge. TDS would be greatly increased due to the ions in the water from mining.
And thats really all you need to look at.
I got exactly the same except either A or B for question 12. I think A.independantz said:1-A
12-D- but ppl are saying the answer is A not entirely sure
14-C- answer is B forgot to divide by the volume to find concentration then log it >.>
That's what i got, so far 2 wrong ...>.>
that was my reasoning. spent ages with plenty of calculations to no avail. had to move on so picked C. however, if u remember the titration topic, the whole equivalence point thing, u notice how once equivalence is reached, it very quickly reaches the extreme, hence 2.7 is believable.Propadanda said:And can someone please explain to me how the fuck you can add a strong acid to a strong base, in relatively similar proportions (not identical, but similar), and end up with a very acidic final pH? I thought Q14 had to be at least C or D. I thought because the weren't in proportion it would be C but then I thought that was still too acidic to have a pH of 4...so I put D, even though it obviously wasn't a perfect neutralisation but ehhh.
my god i was SO CLOSE! i got the 0.1 x 10^-3 difference, but stalled there!! ahh dammit!! coulda got 15/15Propadanda said:n[H+] = .02 x .08
= 1.6 x 10^-3
n[OH-] = .05 x .03
= 1.5 x 10^-3
Therefore, H+ is in excess, and 1 x 10^-4 is left over after mix.
New volume = .05 L
Therefore [H+] = 1 x 10^-4 / .05
Well I'm an idiot.
I skipped a step there somewhere but that's the gist of it.
lol r u fo' srs?berna007 said:product side = left side actually..
just look at the question okay!!!!