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Section I - Multiple Choice (1 Viewer)

deswa1

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Why are we still discussing 10 lol- its definitely B. A and D are odd between symmetrical limits so they don't work and C is below the y axis for all x in the domain.

Though I only got 9/10 for MC :(- I put C for Q8.
 

someth1ng

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This is what I have, they should be mostly correct:
1. D
2. D
3. A
4. A
5. C
6. B
7. A
8. B
9. C
10. B

For Q10, I didn't know how to solve it...so what I did was sub in the limits twice, whichever showed two positive numbers was my answer (B).
 

lonelynight99

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This is what I have, they should be mostly correct:
1. D
2. D
3. A
4. A
5. C
6. B
7. A
8. B
9. C
10. B

For Q10, I didn't know how to solve it...so what I did was sub in the limits twice, whichever showed two positive numbers was my answer (B).
I think 3=C coz it conjugate of z not z
 

Nooblet94

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This is what I have, they should be mostly correct:
1. D
2. D
3. A
4. A
5. C
6. B
7. A
8. B
9. C
10. B

For Q10, I didn't know how to solve it...so what I did was sub in the limits twice, whichever showed two positive numbers was my answer (B).
This is why MC is a stupid idea. You can just get lucky.
 

kman16

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My results:
1. D
2. D
3. A ITS "A". Conjugate Z is a reflection about the x-axis. Then multiplication of "i" rotates it 90degrees anticlockwise.
4. A
5. C
6. B
7.A
8. A
9. C
10. B B is the only even funtion which will give a positive area.

Now that i look back on it I've realised that Q8 is B. Looks like a 9/10 for me
 

SuperSemen

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3 is definitely A, just sub in numbers, i.e z = 1 + i => conj z = ( 1 - i )i = i + 1 , still in first quad.
 

ademb13

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the last one was b. all integrals are odd except that one, which is even and the integral will be greater than 0 :)
 

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