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Section II (1 Viewer)

lolrofllol

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26 a) iii) <p>
i wrote if there were same amount of boys and girls since both were in a 25% range (boys upper quartile = 25% of them, girls upper extreme = 25% of them) <p>
<p>
26 b) iii) did anyone else get 8 am thursday?
<p>
<p>
23 d) ii) was it $11
<p>
<p>
25 c) i) since it asked for simpson's rule and not two applications of simpsons rule (as it usually does in exams) i only did one application on the lake itself. Could this be correct? I got 12/3(0 + (4*28) + 15), can't remember the answer sorry
<p>
<p>
25d) ii) 83.85%?
 
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nah i got for 26 b iii) 8pm wednesday and for 23d i)i got 12.5 because -monthly account fee- 45 net withdrawals = 1.52 mybank = 1eftpos = 22 cash withdraws = 4
 

hazza9

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I also did only one application of simpsons rule of the lake bacause of the same reason. Doesn't make sense why it wouldn't be correct.
 

noturningback

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but wasn't the lake in the middle? not the upper or lower grass?
i dont have the paper :mad:
 

hazza9

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but wasn't the lake in the middle? not the upper or lower grass?
i dont have the paper :mad:
Yea but you could still get the heights for the lake from the heights above and below the lake. Then i just put these into simpsons rule? Do u remember hat answer u got? i dnt have the paper either
 

hassan21291

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OK ..........you know why i left the back page out ..... coz i am sooo dumb !!!! :( ......... my mind was in sequence mode ..... every question except for 23 and 28 was to tages side by side ..... so i just assumed...... hey i might just check over my work seeing as im finished with 20 mins to go ......... and THE LAST TWO QUESTIONS WERE EASY !!!! ........ 7 marks down the toilet
 

Sau

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My favourite question was the one about Bozo the Clown and the lake. I laughed.
yeah that was a funny questiongeneral maths really make you imagine thingsbut the one thing i hat is the question nearly a page long and the question just says to find blah blah blah =="
 

wayne_d

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The lake question required the calculation of the total area of the square, and then the subtraction of the surrounding area of the lake, by using two calculations of the simpsons rule
 

emma211

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The lake question required the calculation of the total area of the square, and then the subtraction of the surrounding area of the lake, by using two calculations of the simpsons rule
yep thats what i did
 

cjosie16

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Can someone explain to be the probabilities in the raffles....

it threw me, i ended up saying:

1/3 x 2/100

and

2/3 x 1/100 + 1/100

which is equal chance.....

Thankyou
 

lookleft

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Negative. First chick has 2/100 chance of winning AT LEAST ONE PRIZE The at least bit is the key to to the qn. Therefore, the second chick has the probability of winning both, winning first one and not the second, and winning the second and losing the first one. Like this: (1/100 x 1/100) + (99/100 x 1/100) + ( 1/100 x 99/100) = 199/10,000 That's what I got. So first chick has a 2/100, or a 200/10,000 chance of winning at least one prize. The second chick has a 199/10,000 chance of winning at least one prize.
there cjosie16
 

Nivek5

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The simpsons rule one is this


4 ( 20 + 20 + 10 ) + 4 (35+88+30)
200+612= 812

Then 55 x 24 = 1320

Lake = 1320-812 = 508 M Squared



ii)


508x0.6 = 304.8 M Cubed

304.8x 1000L= 304800L

304800L /4L = 76200 fillings of the bucket
 
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Enchantress91

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Can someone explain to be the probabilities in the raffles....

it threw me, i ended up saying:

1/3 x 2/100

and

2/3 x 1/100 + 1/100

which is equal chance.....

Thankyou

To previous posters, I reckon it was:

Mary's chance: 2/100
Jane's chance: 2/200

(Because Jane bought 2 tickets out of 200) So Mary's more likely to win.:)
 

noturningback

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The simpsons rule one is this


4 ( 20 + 20 + 10 ) + 4 (35+88+30)
200+612= 812

Then 55 x 24 = 1320

Lake = 1320-812 = 508 M Squared



ii)


508x0.6 = 304.8 M Cubed

304.8x 1000L= 304800L

304800L /4L = 76200 fillings of the bucket
wooo yep thats what I thought caus the lake was in the middle
I was worrying when people were saying they only did one application of the rule
 

noturningback

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Nope

P(Win 1st and lose 2nd) + P(Lose 1st and win 2nd)

= (1/100 x 99/100) + (99/100 x 1/100)

:)
 

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