sulfate reducing bacteria equations (1 Viewer)

pqd

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From what I have seen, there are two equations describing the reduction of sulfate:
SO42- + 10H+ + 8e---> H2S + 4H2O
SO42- + 5H2O + 8e---> HS- + 9OH-

My guesses as to why this is are either:
1. the first equation occurs in acidic conditions hence the H ions but the second occurs under more neutral conditions
2. the equations are equivalent in terms of what actually happens and some atoms are omitted

Can someone please clarify and if they are equivalent, can someone show me how
 

mjrow

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That is only the first equation. You need to include the oxidation of the artefact (eg. iron) and then combine the two to show the production of more H ions. (I use the first equation)
 

Queenroot

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From what I have seen, there are two equations describing the reduction of sulfate:
SO42- + 10H+ + 8e---> H2S + 4H2O
SO42- + 5H2O + 8e---> HS- + 9OH-

My guesses as to why this is are either:
1. the first equation occurs in acidic conditions hence the H ions but the second occurs under more neutral conditions
2. the equations are equivalent in terms of what actually happens and some atoms are omitted

Can someone please clarify and if they are equivalent, can someone show me how
Don't use the second one
 

strawberrye

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The two equations are NOT equivalent, they refer to sulphate-reducing bacteria reaction under different conditions.
 

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