cardinalsfan70
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correct based on my own experiences.emo-kid-91 said:discussion among my classmates afterwards revealed 10a - integrating a log - wasn't something we're taught in 2u.
correct based on my own experiences.emo-kid-91 said:discussion among my classmates afterwards revealed 10a - integrating a log - wasn't something we're taught in 2u.
Thats what I got!minijumbuk said:Solutions to 10a)
y = ln (x-2)
ey = x - 2
x = ey + 2
A = 7ln 5 -∫ln 50(ey + 2)dy
= 7ln 5 - [ey + 2y]ln 50
= 7ln 5 - [eln 5 + 2ln 5 - e0 - 2(0)]
= 7ln 5 - 5 - 2ln 5 + 1
= 5ln 5 - 4
in 2u u r not ment to know how to integrate a log but u can still do that question. u have to first find the area of the rectangle, which was 7ln5 asemo-kid-91 said:discussion among my classmates afterwards revealed 10a - integrating a log - wasn't something we're taught in 2u.
ha me too, with the whole integrating a log thing. i know exactly what i had to do, my friend told me as soon as we got outside, and i was just like, dammit. i left out 15 marks... i just hope i get in the 80s ha.Alex499 said:I'll be lucky to pass.
DAMN that was the worst test ever.
And I sure as hell never learnt to integrate logs. I just left it the same and integrated it with the hope that I might get a sympathy mark
yeah but you didnt have to - u had to make x the subject and use the y axis so that you integrated sumthing like e^Y...not integration of logsemo-kid-91 said:discussion among my classmates afterwards revealed 10a - integrating a log - wasn't something we're taught in 2u.
that is so simple now.minijumbuk said:Solutions to 10a)
y = ln (x-2)
ey = x - 2
x = ey + 2
A = 7ln 5 -∫ln 50(ey + 2)dy
= 7ln 5 - [ey + 2y]ln 50
= 7ln 5 - [eln 5 + 2ln 5 - e0 - 2(0)]
= 7ln 5 - 5 - 2ln 5 + 1
= 5ln 5 - 4
heeey, i did exactly the same mistake but when i checked it i found it...but yeah u shud get marks just maybe 1 offpookins said:I think I got around 118
BUT I know i made a mistake in 10b, I accidently left out a ^2 on the L, and therefore my answer was sqrt(L/2) instead of L/sqrt2.
As it was a mistake, and when you look at it you can see i've left out the ^2, do you think I could still get a mark for that? because I know at my school they have this way of marking, that if you make a small error, and not something you obviously don't know, they don't penalise you for it... kind of like a transcription error...
The question was out of 3, do you know how many marks i could get? I did everything else right in the question, just that error... =(
This is what i did.minijumbuk said:METHOD 2: (The way I did it)
d/dx (x-2)ln (x-2)
= (x-2)/(x-2) + ln (x-2)
= ln (x-2) +1
Therefore ∫ (ln (x-2) +1)dx = (x-2)ln (x-2)
∫73 ln (x-2) dx = [(x-2)ln (x-2)]73 - ∫73dx
= 5ln5 - 3ln 1 - [x]73
= 5ln 5 - 7 + 3
= 5ln 5 - 4