Aysce

Aysce

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  • RishBonjour
    Today at 7am you sent me the message? LOL you check bos before school?
    just got back from tutoring man (9.30 pm) fkkk 4u test tommorow
    T
    Yeah. It's a bit hard to explain but it was a trapezium inside a circle. Circle's diameter was 10 and the the base of the trapezium was the diameter. The opposite side was a chord on the circle. The question was find max area. There was a little bit more information but you get my drift
    T
    ugh they are painful. The test was nice though. They broke it up into 3 questions for me but hopeless me couldn't get the last one out. 5/30 marks gone.
    bleakarcher
    the question identifies the variables for you, or most of them for that matter. start off by finding an equation which relates the two variables then find the formula for some quantity which needs to be maximised/minimised in terms of the two variables. now, you want the formula in terms of only a single variable and so throughout the relationship between the two variables you would have developed at the beginning, substitute one variable so that the formula is now in terms of a single variable. carry on to find the stationary pts of the quantity which is said to be maximised/minimised and then you should be able to answer.
    A
    Okay, so let the roots be a, a, b
    Their sum is 2a + b = -m
    Product is a^2 * b = 7
    Sum two at a time is 2ab + a^2 = -15
    Solve simultaneously and you'll get m
    Cheers
    S
    No, e^-x(x-1) if you differentiate that you get (2-x)e^-x. Differentiating xe^-x will get you e^-x (1-x). Where did you get this question?
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