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You could use a few different methods to determine the acceleration due to gravity at the earth's surface maybe?

Ahh crap... my triangle didn't work :( Edit: Thanks withoutaface :)

Do it like this, at least it's a proof: sin^-1x = cos^-1x let y = cos^-1x x = cos y Draw up a triangle, trying my best here.... fffffffffffffffffffffffffff/| ffffffffffffffffffffffffff/ | ffffffffffffffffffffff1 /ff|....sqrt(1-x²)...

I'm confused. I'm sure this is a very simple question, but I'm not sure how to do it. It was Q 19 of the multiple choice in 2002. Anyways here it is: Jack's Computer Services Pty Ltd has provided the following data based on the revenue statement for the year ended 30 June 2002. Total...

I think they are both the same ratio, however the second ratio would imply that you don't include current liabilities in the calculation....

When I got a job with Coles, they actual called me and asked me if I wanted to go in for the aptitude test. I never even put in an application form. 3 hours after they called me, I had a job :) Turns out someone who worked there that I knew thought that I might want a job, and they were short...

Question 7 (a) The amount of fuel F in litres required per hour to propel a plane in level flight at constant speed u km/h is given by F = Au³ + B/u where A and B are positive constants. (i) Show that a pilot wishing to remain in level flight for as long a period as possible...

Unfortunately I've managed to run into a few other posts by that guy. I don't think he'll be around for too much longer ;)

hmm.... I dunno

meh, I had to do that before I could attempt (ii)

(i) To remain at level flight for greatest possible time, F is a minimum. F = Au³ + B/u dF/du = 3Au² - B/u² d²F/du² = 6Au + 2B/u³ d²F/du² > 0 since u>0, A & B are positive. Therefore min when...

Can you do part (i)?

hehe... I think I know the reason for that as well. People that had no idea were probably going "Step 1:, let n = 1...." doing the working and getting a mark, then not having a clue about the rest, then writing a concluding statement and getting another mark ;)

Get out of here you dickhead. There is no point in that.

What if the two frames of reference are separated by a big sheet of glass, and one frame of reference had air while the other was a vacuum?

And is it the graph of y = [(x-1)(x-2)/(x-3)]^1/2 or y = [(x-1)(x-2)]^1/2/(x-3) that the question asks?

That is the graph of y² = (x-1)(x-2)/(x-3), not y = [(x-1)(x-2)/(x-3)]^1/2 right?

Ditto.... I came 3rd in the year and I have never studied in my life for Business Studies. It's a good subject to do if you are lazy :)

Chris- what a joke. A guy with one leg can get across a balance beam with little to no problems and Chris can't do it with multiple attempts.

It is beyond me how Rory is still there.