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hand chopped off means u don't have to do your exam... tho the inconvenience seems like it would outweigh that advantage :(

yep, makes sense too :) necklace is a circle HAHA - any luck on qu 2.

nope, not what the book says

I thought this first one would be easy 8 pink beads and 8 white beads make up a necklace. how many ways can the necklace be made if; i) there are no restrictions (2 sig. fig.) i thought 16! -> but thats the wrong solution?? ii) pink and white alternate i thought 8!.8! x2 meh...

ok if e is where the max is, then every other solution must be under it so consider what f(e) = ln e / e = 1/e therefore the max point is (e,1/e) therefore it follows all points are under this point ln x / x < 1/e then work through

very low, beyond 500 most probably (we've only done 2 hsc's)

is my school going to pull my UAI down, i bloody hope not, i worked too hard to not get over 90 thoughts?

do u mean oxygens double bond?

quite right, quite right u could just state # of electrons (obviosuly, not specifically) metals > semi > insult

has to do with the bonding, cuz it has a resonance pattern, and that it has an instable double bond.... blah blah

there is alot to talk about, far too much to type here some starter material - http://hsc.csu.edu.au/chemistry/core/monitoring/chem944/944net.html#net18

I've done this, jst thought i'd let you's have a crack for .... fun By considering (1-x)^n (1 +1/x)^n express, (n 2)(n 0) - (n 3) (n 1) +...+ (-1)^n (n n) (n n-2) where (n n) = nCk in simplest form

transformation method > t-method for all real questions hahaha

- hence Perms/Comb suck.

bugger How is it done then?

Who knows, my teacher said that they'll most probably go 2 religious rites from 2 religious traditions, and make it a 20 marker.... cuz lately thats what they are doing (so she says).

yes, we don't need to know this crap - LoL

;) god i hate chemistry :( Oh and the practical is testing various saccharides (spelling?) with Benedicts solution, if the sugar is reducing, it will cause the Copper ions to reduce in the solution causing the colour to go browny - hope that helps (you dont really need to know the...

Reducing sugars contain either a free aldehyde group ( O=C-H) or a free ketose group ( O=C) :)

we don't need to draw them, just describe them relative to eachother, e.g starch has more branches than cellulose etc....