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I thought that 'the box method' and 'the second derivative method' were two different methods of determining the nature of stationary points. 'The box method' uses the first derivative and then looks at the slope (+, -, 0).

Re: HSC 2014 4U Marathon - Advanced Level Ah k. I thought you were meaning the upside-down T symbol: http://en.wikipedia.org/wiki/Coprime_integers

Re: HSC 2014 4U Marathon - Advanced Level It means 'is coprime to'.

This thread is now my discovery related text

inb4thepersonwhoactuallycamesecondwasEmma

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Re: HSC 2014 4U Marathon (2000 Q5i) Consider the polynomial: p(x) = ax^4 + bx^3 + cx^2 + dx + e, where a, b, c, d and e are integers. Suppose n is an integer such that p(n) = 0. Prove that n divides e.

I'm good :P. U? How's yr12?

Rekt /thread

In terms of university, general maths is rarely a prerequisite, although it is sometimes for things such as primary school teaching. Ofc any type of maths would be handy to do so it just depends on how well you are doing in history and maths, how much you like them and what kind of marks you...

It's because principle arg is defined from -pi<=x<=pi. Moving from positive x-axis to the positive y-axis is a movement of pi/2. So to go the reverse, moving from positive x axis to the negative y axis must be a movement of -pi/2. 3i = 3cispi/2 and -3i =3cis-pi/2, you will get these results if...

I would start another thread, but this does have to do with complex numbers... How often should I be using the complex numbers mode on my calculator to solve things that have 'i' in them, do the markers want to see all of the calculation steps when for example you are finding remainders by...

Yes, that's it. You simply place the first root at (-1,0) and the roots are equally spaced out from there.

With this, how do you know that the remainder is linear? (Or does it not matter)

Hey Sean I'm interested in learning more about Complex Analysis (which you already listed) and Hilbert Space.

Re: HSC 2014 4U Marathon I did it using complex numbers, I think this works: a+11i rotated pi/3 = b+37i. So (a+11i) x cispi/3 = b+37i, then solving the real and imaginary parts makes ab = 21root3 x 5root3 = 315

Re: HSC 2014 4U Marathon - Advanced Level Lol I just realised what I was doing wrong with the similar triangles :S...

Re: HSC 2014 4U Marathon - Advanced Level Does this work? Let A, B, C and D be the sides of a cyclic quadrilateral and E be an external point and let two equal tangents from the external point E meet the circle at A and C. Any secant that passes through E, B and D is a diagonal to the...

Re: HSC 2014 4U Marathon - Advanced Level Can I ask how you know to turn that statement into that sum?

Imo graphing is the fastest way. If you do a 5sec sketch, you can tell by inspection that it is -2 <= x <=3. Then by looking at the answers, the very first one I tried out was c) simply because it had the right boundaries.