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  1. Fizzy_Cyst

    HSC Physics Marathon 2013-2015 Archive

    re: HSC Physics Marathon Archive Is that your answer? If so, nope :)
  2. Fizzy_Cyst

    HSC Physics Marathon 2013-2015 Archive

    re: HSC Physics Marathon Archive Question: 3 moons, X, Y and Z are in orbit around the same planet. The moons have identical orbital speeds, but masses of M, 9M and 25M respectively. Determine the ratio of their orbital radii and justify your answer.
  3. Fizzy_Cyst

    How to study?

    I have found that past papers are by far the most effective. Of course there are those memorisation dot points, which you just need to be able to spew information back out, but once you are sweet with those dot points, focus on past papers
  4. Fizzy_Cyst

    projectile q

    What he did above but replace Sy = Uyt + ½ayt with Sy = Uyt + ½ayt^2 then t = sqrt (300/4.9) then follow my answer
  5. Fizzy_Cyst

    projectile q

    you forgot to square the t in your equation! Sx = 75 x sqrt(300/4.9) Sx = 586.85m
  6. Fizzy_Cyst

    HSC Physics Marathon 2013-2015 Archive

    re: HSC Physics Marathon Archive Right approach, finding both proper time and dilated time, but you have made a boo boo with the t0 when calculating dilated time :) btw, strong first post! :) According to what you have done, A should age ~27 years, but B only ages 20 years. The person who...
  7. Fizzy_Cyst

    HSC Physics Marathon 2013-2015 Archive

    re: HSC Physics Marathon Archive Not that simple. :) Show me the working!!
  8. Fizzy_Cyst

    HSC Physics Marathon 2013-2015 Archive

    re: HSC Physics Marathon Archive Person A and Person B both fly to a planet which is 25 light years away. Person B flies at 0.8c and Person B flies at 0.6c. When both people arrive, who is older and by how much?
  9. Fizzy_Cyst

    Chem textbooks

    IMO: Conq Chem = not enough info Jacaranda = too much info Take them both, spending half your time on each and by law of averages, you will have it just right
  10. Fizzy_Cyst

    Physics Tutoring for HSC 2015 -- NEED BAND 6 STUDENTS!!! PROVEN RESULTS!!!

    Starting M & G on January 10, 2015. Still space in one of my classes, contact me for more info
  11. Fizzy_Cyst

    Which was meant to be the slower light beam in the Michelson Morley experiment?

    As above, focus on the CHANGE in interference pattern which was expected when the device was rotated. Here is a cool flashlet to allow you to visualise the motion of the beams as they split into perpendicular components...
  12. Fizzy_Cyst

    The Screenshots & Video Thread

    Making me want to start up my old gaming pc and post pics of me with 4 headshots on de_dust !!
  13. Fizzy_Cyst

    Sid Meier's Civilization: Beyond Earth

    :O I still remember playing the original, lmfao.
  14. Fizzy_Cyst

    Hey mate, Nah, I wouldn't like to do that, sorry :( Some of my ex-students do have notes from...

    Hey mate, Nah, I wouldn't like to do that, sorry :( Some of my ex-students do have notes from other tutoring places though, if you would be interested in that, let me know and I will give your their contact details (Matrix, Talent 100 etc...)
  15. Fizzy_Cyst

    Physics Tutoring for HSC 2015 -- NEED BAND 6 STUDENTS!!! PROVEN RESULTS!!!

    1 class for HSC 2016 filled already :smile:
  16. Fizzy_Cyst

    Physics version of easychem?

    Not afaik There should be one soon though ;)
  17. Fizzy_Cyst

    MC7: Controversial answer (A)

    Whilst I agree with what you are saying, it perhaps is not CRYSTAL clear, by using this logic, you could also say that the induced flux will be greater than the flux from the magnet itself (if the magnet is moved REALLY fast), seeing as the velocity of the magnet relative to the coil is not...
  18. Fizzy_Cyst

    DC-->AC?

    Longer wavelength LEDs require lower voltages, but even red LED's still require ~2V
  19. Fizzy_Cyst

    DC-->AC?

    You, my friend, have broken fizzicks! Are you sure you have connected the LED the correct way? One way they will work, the other they won't
  20. Fizzy_Cyst

    MC Q17

    Answer is B. equate F = Ma with F = qE a = qE/m q of alpha = 2x q of proton m of alpha = 4 x m of proton a of alpha = 1/2 a of proton
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