a) First find the gradient of tangent to curve at x=2.
y=x^2 -> y'=2x.
sub x=2 into y'.
y'=4. So gradient is of tangent to curve at x= 2 is 4.
since normal is perpendicular to tangent, gradient of normal is -1/4 (ie. the negative recipricol)
y value of curve y=x^2 when x=2 is 4.
now.
use...